6. ZigZag Conversion

Posted 2020-11-11 谦曰盛

Description:

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string s, int numRows);

　　

Examples:

Input: s = "PAYPALISHIRING", numRows = 3
Output: "PAHNAPLSIIGYIR"

Input: s = "PAYPALISHIRING", numRows = 4
Output: "PINALSIGYAHRPI"
Explanation:

P     I    N
A   L S  I G
Y A   H R
P     I　

Solutions:

 

class Solution(object):
    def convert(self, s, numRows):
        """
        :type s: str
        :type numRows: int
        :rtype: str
        """
        if numRows == 1 or numRows >= len(s):  # 如果“行”数为一或者字母数小于“行”数
            return s

        L = [‘‘] * numRows  #
        index, step = 0, 1

        for x in s:
            L[index] += x   # 不太好理解？
            if index == 0:
                step = 1
            elif index == numRows -1:
                step = -1
            index += step

        return ‘‘.join(L)