POJ1008 Maya Calendar

Posted 2020-11-10 参婵

Maya Calendar

Time Limit: 1000MS		Memory Limit: 10000K
Total Submissions: 82185		Accepted: 25234

Description

During his last sabbatical, professor M. A. Ya made a surprising discovery about the old Maya calendar. From an old knotted message, professor discovered that the Maya civilization used a 365 day long year, called Haab, which had 19 months. Each of the first 18 months was 20 days long, and the names of the months were pop, no, zip, zotz, tzec, xul, yoxkin, mol, chen, yax, zac, ceh, mac, kankin, muan, pax, koyab, cumhu. Instead of having names, the days of the months were denoted by numbers starting from 0 to 19. The last month of Haab was called uayet and had 5 days denoted by numbers 0, 1, 2, 3, 4. The Maya believed that this month was unlucky, the court of justice was not in session, the trade stopped, people did not even sweep the floor.

For religious purposes, the Maya used another calendar in which the year was called Tzolkin (holly year). The year was divided into thirteen periods, each 20 days long. Each day was denoted by a pair consisting of a number and the name of the day. They used 20 names: imix, ik, akbal, kan, chicchan, cimi, manik, lamat, muluk, ok, chuen, eb, ben, ix, mem, cib, caban, eznab, canac, ahau and 13 numbers; both in cycles.

Notice that each day has an unambiguous description. For example, at the beginning of the year the days were described as follows:

1 imix, 2 ik, 3 akbal, 4 kan, 5 chicchan, 6 cimi, 7 manik, 8 lamat, 9 muluk, 10 ok, 11 chuen, 12 eb, 13 ben, 1 ix, 2 mem, 3 cib, 4 caban, 5 eznab, 6 canac, 7 ahau, and again in the next period 8 imix, 9 ik, 10 akbal . . .

Years (both Haab and Tzolkin) were denoted by numbers 0, 1, : : : , where the number 0 was the beginning of the world. Thus, the first day was:

Haab: 0. pop 0

Tzolkin: 1 imix 0
Help professor M. A. Ya and write a program for him to convert the dates from the Haab calendar to the Tzolkin calendar.

Input

The date in Haab is given in the following format:
NumberOfTheDay. Month Year

The first line of the input file contains the number of the input dates in the file. The next n lines contain n dates in the Haab calendar format, each in separate line. The year is smaller then 5000.

Output

The date in Tzolkin should be in the following format:
Number NameOfTheDay Year

The first line of the output file contains the number of the output dates. In the next n lines, there are dates in the Tzolkin calendar format, in the order corresponding to the input dates.

Sample Input

3
10. zac 0
0. pop 0
10. zac 1995

Sample Output

3
3 chuen 0
1 imix 0
9 cimi 2801

Source

Central Europe 1995

 

 

起初以为是自己输入输出方式有问题，百度发现自己没有考虑（yr%260==0&&!yr) 时需要减一。结果还是不对，最后发现自己数组少复制了一个字符串，很难受。但是题目中是没有的，这还是我看AC的代码发现的。以为肯定没错的地方错了，肯定错了的地方没错。。还是考虑不够，不熟悉规范。无话可说。

 

#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
char Haab[19][10]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"},
     Tzolkin[20][10]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};

int main()
{
    int N,i,j;
    int num,yr,ndays,mon;
    char name[10],ch;
    scanf("%d",&N);
    printf("%d\n",N);
    for(i=0;i<N;i++)
    {
        cin>>num>>ch>>name>>yr;
        for(j=0;j<19;j++)
            if(!strcmp(Haab[j],name))
            {
                break;
            }
        ndays=365*yr+j*20+num;
        yr=ndays/260;
        num=ndays%260%13+1;
        mon=ndays%260%20;
        if(!ndays%260&&ndays)
            yr--;
        cout<<num<<‘ ‘<<Tzolkin[mon]<<‘ ‘<<yr<<endl;
    }
    return 0;
}