行列转换

Posted 2020-11-07 一个写代码的人

https://blog.csdn.net/mchdba/article/details/39163695

第一步，求两个表各自的数据
select DATE(a.create_date) as ‘nianfen‘,
sum(IF(a.type="0",1,0)) AS "shanghu",
SUM(IF(a.type="1",1,0)) AS "banzu",
SUM(IF(a.type="2",1,0)) AS "company",
0 as ‘zhaogong‘,
0 as ‘zhaohuo‘,
0 as ‘gongqiu‘,
0 as ‘gongcheng‘,
0 as ‘jianshe‘,
0 as ‘tujian‘,
0 as ‘advert‘,
0 as ‘dianqi‘,
0 as ‘yuanlin‘
from
dp_info a where DATE_FORMAT(create_date,‘%Y-%m‘)=‘2018-05‘
group by DATE(a.create_date)

union all

select DATE(a.date) as ‘nianfen‘,
0 as ‘shanghu‘,
0 as ‘banzu‘,
0 as ‘company‘,
sum(IF(a.to_type="招工信息",1,0)) AS "zhaogong",
SUM(IF(a.to_type="找活信息",1,0)) AS "zhaohuo",
SUM(IF(a.to_type="供求信息",1,0)) AS "gongqiu",
SUM(IF(a.to_type="工程机械",1,0)) AS "gongcheng",
SUM(IF(a.to_type="建设服务",1,0)) AS "jianshe",
SUM(IF(a.to_type="土建材料",1,0)) AS "tujian",
SUM(IF(a.to_type="装修材料",1,0)) AS "advert",
SUM(IF(a.to_type="电气材料",1,0)) AS "dianqi",
SUM(IF(a.to_type="园林景观",1,0)) AS "yuanlin"
from
fb_fabu a where DATE_FORMAT(date,‘%Y-%m‘)=‘2018-05‘
group by DATE(a.date)

 

第二步，求两个表合在一起的数据
select
xx.nianfen as ‘nianfen‘,
sum(xx.zhaogong) as "zhaogong",
sum(xx.zhaohuo) as ‘zhaohuo‘,
sum(xx.gongqiu) as ‘gongqiu‘,
sum(xx.gongcheng) as ‘gongcheng‘,
sum(xx.jianshe) as ‘jianshe‘,
sum(xx.shanghu) as ‘shanghu‘,
sum(xx.company) as ‘company‘,
sum(xx.banzu) as ‘banzu‘,
SUM(xx.tujian) AS "tujian",
SUM(xx.advert) AS "advert",
SUM(xx.dianqi) AS "dianqi",
SUM(xx.yuanlin) AS "yuanlin",
SUM(xx.tujian) AS "tujian"
SUM(IF(a.to_type="园林景观",1,0)) AS "yuanlin"
from
(
第一步内容
) xx
GROUP BY xx.nianfen

第三步，求和
select
‘总计‘ as ‘nianfen‘,
sum(ddd.zhaogong) as "zhaogong",
sum(ddd.zhaohuo) as ‘zhaohuo‘,
sum(ddd.gongqiu) as ‘gongqiu‘,
sum(ddd.gongcheng) as ‘gongcheng‘,
sum(ddd.jianshe) as ‘jianshe‘,
sum(ddd.shanghu) as ‘shanghu‘,
sum(ddd.company) as ‘company‘,
sum(ddd.banzu) as ‘banzu‘,
SUM(ddd.tujian) AS "tujian",
SUM(ddd.advert) AS "advert",
SUM(ddd.dianqi) AS "dianqi",
SUM(ddd.yuanlin) AS "yuanlin"
from
(
第二步的内容
）ddd

第四部合并