PAT (Advanced Level) 1039. Course List for Student (25)
Posted Fighting Heart
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了PAT (Advanced Level) 1039. Course List for Student (25)相关的知识,希望对你有一定的参考价值。
map会超时,二分吧...
#include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<vector> using namespace std; int n,m; int tot; vector<int>v[50000]; struct X { int id; int num; char name[210][6]; }s[2600]; struct Name { char name[6]; }op[40010]; bool cmp2(const Name&a,const Name&b) { return strcmp(a.name,b.name)<0; } bool cmp(const X&a,const X&b) { return a.id<b.id; } char quary[40010][6]; int main() { scanf("%d%d",&n,&m); for(int i=1;i<=m;i++) { scanf("%d",&s[i].id); scanf("%d",&s[i].num); for(int j=1;j<=s[i].num;j++) scanf("%s",s[i].name[j]); } for(int i=1;i<=n;i++) { scanf("%s",op[i].name); strcpy(quary[i],op[i].name); } sort(op+1,op+1+n,cmp2); sort(s+1,s+1+m,cmp); for(int i=1;i<=m;i++) { for(int j=1;j<=s[i].num;j++) { int h=0; int l=1,r=n; while(l<=r) { int mid=(l+r)/2; if(strcmp(op[mid].name,s[i].name[j])<0) l=mid+1; else if(strcmp(op[mid].name,s[i].name[j])>0) r=mid-1; else { h=mid; break; } } if(h==0) continue; v[h].push_back(s[i].id); } } for(int i=1;i<=n;i++) { int q=0; int l=1,r=n; while(l<=r) { int mid=(l+r)/2; if(strcmp(op[mid].name,quary[i])<0) l=mid+1; else if(strcmp(op[mid].name,quary[i])>0) r=mid-1; else { q=mid; break; } } if(q==0) continue; printf("%s ",quary[i]); printf("%d",v[q].size()); for(int j=0;j<v[q].size();j++) printf(" %d",v[q][j]); printf("\n"); } return 0; }
以上是关于PAT (Advanced Level) 1039. Course List for Student (25)的主要内容,如果未能解决你的问题,请参考以下文章