算法获取两个数组所有结合的结果。

Posted 2020-11-03 流星泪

        /// <summary>
        /// 获取两个数组的所有结合的结果值
        /// </summary>
        /// <param name="args"></param>
        static void Main(string[] args)
        {
            var strs1 = new string[] { "w", "q", "b", "s", "g" };
            var strs2 = new string[] { "1", "2", "3" };
            Console.WriteLine(NewString(strs1, strs2)); 
        }

        public static string NewString(string[] strs1, string[] strs2)
        {
            Stopwatch sw = new Stopwatch();
            sw.Start();
            var len1 = strs1.Length;
            var runStr = "";
            for (int i = 0; i < len1-2; i++)
            {
                for (int j = i+1; j < len1-1; j++)
                {
                    for (int k = j+1; k < len1; k++)
                    {
                        runStr += strs1[i] + strs2[0] + strs1[j] + strs2[1] + strs1[k] + strs2[2] + "\\n";
                    }
                }
            }
            sw.Stop();
            Console.WriteLine("运行总时间："+sw.ElapsedTicks +"毫秒");
            return runStr;
        }

　　

效果展示：