258. Add Digits
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Problem:
Given a non-negative integer num
, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38
, the process is like: 3 + 8 = 11
, 1 + 1 = 2
. Since 2
has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
A possible solution:
int addDigits(int num) { int temp; while(num >= 10) { while(num >= 10) { temp += num%10; num = num/10; } num += temp; temp = 0; } return num; }
more efficient way:
int addDigits(int num) { return (num-1)%9 + 1; }
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