Createfile打开磁盘的格式要求

Posted 2020-11-01 piaoxuewaiwai

转载：https://blog.csdn.net/dongpanshan/article/details/7860790
createfile可以打开文件、通道、邮槽、通信资源、磁盘驱动器（仅适用于 windowsNT ）、控制台、文件夹（仅用于打开）   //来自https://www.cnblogs.com/findumars/p/5636108.html
我就说咯，明明我使用FILE_READ_ATTRIBUTES模式已经成功打开了磁盘的，今天居然打不开，原来是格式错误了。
HANDLE CreateFile(
  LPCTSTR lpFileName, 
  DWORD dwDesiredAccess, 
  DWORD dwShareMode, 
  LPSECURITY_ATTRIBUTES lpSecurityAttributes, 
  DWORD dwCreationDisposition, 
  DWORD dwFlagsAndAttributes, 
  HANDLE hTemplateFile
); 

 

 

Parameters

lpFileName

[in] Pointer to a null-terminated string that specifies the name of the object, such as file, COM port, disk device, or console, to create or open.

If *lpFileName is a path, there is a default string size limit of MAX_PATH characters. This limit is related to how the CreateFile function parses paths.

When lpFileName points to a COM port to open, you must include a colon after the name. For example, specify COM1: to open that port. When using IrCOMM, specify COM3:.

 

 

在msdn查找CreateFile打开磁盘时对lpFileName的说明不太清楚，特此说明一下，CreateFile打开磁盘时，lpFileName的格式必须为"\\\\\\\\.\\\\C:"(打开C盘)，"\\\\\\\\.\\\\D:"(打开D盘)

程序如下：访问C盘

 

hFile = CreateFile("\\\\\\\\.\\\\C:",
                       GENERIC_READ|GENERIC_WRITE,
                       FILE_SHARE_READ,
                       NULL,
                       OPEN_EXISTING,
                       0, 
                       NULL);