LeetCode:Intersection of Two Arrays II
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Intersection of Two Arrays II
Total Accepted: 1340 Total
Submissions: 3078 Difficulty: Easy
Given two arrays, write a function to compute their intersection.
Example:
Given nums1 = [1, 2, 2, 1]
, nums2 = [2,
2]
, return [2, 2]
.
Note:
- Each element in the result should appear as many times as it shows in both arrays.
- The result can be in any order.
Follow up:
- What if the given array is already sorted? How would you optimize your algorithm?
- What if nums1‘s size is small compared to num2‘s size? Which algorithm is better?
- What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
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java code:
public class Solution { public int[] intersect(int[] nums1, int[] nums2) { int len1 = nums2.length,len2 = nums2.length; List<Integer> list = new ArrayList<Integer>(); List<Integer> interList = new ArrayList<Integer>(); for(int num:nums1) { list.add(num); } for(int i=0;i<len2;i++) { if(list.contains(nums2[i])) { interList.add(nums2[i]); list.remove(list.indexOf(nums2[i])); } } int[] ret = new int[interList.size()]; int cnt = 0; for(int num:interList) { ret[cnt++] = num; } return ret; } }
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