老男孩作业day1—用户登陆

Posted 2020-10-31 jieranfeng

跟着老男孩培训写的第一次作业

需求：

1、用户可以通过用户名和密码登陆；

2、密码输入错误三次后即锁定用户

3、把用户名、密码、锁定后的用户放在文件里

4、如果没有该用户提示还没有注册

5、使用锁定的用户登陆会提示此用户已经被锁定了

 1 #! /usr/bin/env python
 2 # -*- coding:utf-8 -*-
 3 
 4 username = raw_input("username: ")
 5 password = raw_input("password: ")
 6 
 7 
 8 # 把用户文件放到字典里面，更加容易匹配
 9 def read_config():
10     with open(r‘E:\\coding\\oldboy\\practice_day1\\user_info‘, ‘r‘) as f:
11         user_dict={}
12         for line in f.readlines():
13             user_info = line.strip().split(‘=‘)
14             user_dict[user_info[0]] = user_info[1]
15             # user_dict[‘password‘] = user_info[3]
16     return user_dict
17 
18 
19 # 检查输入的用户是否在黑名单里，如果在，显示已经在黑名单里面
20 def chack_locked():
21     with open(r‘E:\\coding\\oldboy\\practice_day1\\lock_info‘, ‘r‘) as f_lock_info:
22         if username in f_lock_info.read():
23             print("You are locked")
24             exit(0)
25 
26 
27 # 密码输入错误后重新输入，超过三次则会停止输入密码
28 def input_again():
29     count = 0
30     while count < 2:
31         print("It is wrong password")
32         password = raw_input("password again: ")
33         if password in read_config()[‘password‘]:
34             print(‘congratulition‘)
35             break
36         else:
37             count += 1
38     else:
39         print("Sorry")
40     return count
41 
42 
43 # 如果输入密码错误三次，则自动把用户添加到黑名单里面
44 def locked(count):
45     if count == 2:
46         with open(‘E:\\coding\\oldboy\\practice_day1\\lock_info‘, ‘a‘) as f_lock:
47             f_lock.write(username)
48 
49 
50 if __name__ == ‘__main__‘:
51     chack_locked()
52     user_dict = read_config()
53     if username == user_dict[‘username‘] and password == user_dict[‘password‘]:
54         print("Welcome to login")
55     elif username != user_dict[‘username‘]:
56         print("No user, please sign up")
57     elif username == user_dict[‘username‘] and password != user_dict[‘password‘]:
58         count = input_again()
59         locked(count)

仍然存在的问题：

1、用户文件里无法添加多个用户，只能有一个用户登陆，把用户存放字典时，因为字典的键唯一，所以只能保存后面的用户信息