python ABC

Posted 2020-07-09 sunny,lee

因为项目需要，总是会有各种各样要重命名文件的场合，manual的方法当然不可取，bat的方法又感觉不够强大，所以就从零开始学python，就为了能够自动批量修改文件名，倒腾了一个周六，总算可以了 :)

效果呢？就是把文件从

XXXXX0.bin

XXXXX2.bin

XXXXX4.bin

XXXXX5.bin

.....

 

转化成了

0.bin

1.bin

2.bin

.....

 

方便了程序直接读取这些Bin文件。

 

脚本如下：

import os
path = "C://Users//ll//Desktop//pic"

# 2016/5/21
# rename files in one subfile

#############remove the unnecessary name#############
for file in os.listdir(path):
    #filename = file.split(‘.‘)[0]
    #filenum = filename.split(‘_‘)[6]
    #num = filenum.split(‘D‘)[1]
    #print(file)
    #print(num + ‘.bin‘)
    #os.rename(path + file, num + ‘.bin‘)
    filename = file[58:]
    originname = ‘C://Users//ll//Desktop//pic‘ + ‘//‘ + file;
    newname = ‘C://Users//ll//Desktop//pic‘ + ‘//‘ + filename;
    print(originname);
    print(newname);
    os.rename(originname,newname);
#######################################################

file = os.listdir(path)
print (file)

###########sort#######################################
for i in range(len(file)):
  file[i] = file[i].split(‘.‘)
  file[i][0] = int (file[i][0])
print(‘>>>>>>>>‘)
file.sort()
print(file)

###########rename#####################################
for i in range(len(file)):
  print(file[i])
  file[i][0] = str(file[i][0])
  file[i] = file[i][0] + ‘.‘ + file[i][1]
  newfile = str(i)
  originname = ‘C://Users//ll//Desktop//pic‘ + ‘//‘ + file[i]
  newname = ‘C://Users//ll//Desktop//pic‘ + ‘//‘ + newfile + ‘.bin‘;
  print(originname)
  print(‘new name to be:‘)
  print(newname)
  os.rename(originname,newname)
  print(file[i])
  print(‘\n‘)
print(‘successfully rename file!!! Great Job!!!‘)



input()