Word Reversal

Posted 2020-10-29 王陸

Description

For each list of words, output a line with each word reversed without changing the order of the words.

 

Input

 

The first line contains a positive integer indicating the number of cases to follow. Each case is given on a line containing a list of words separated by one space, and each word contains only uppercase and lowercase letters.

 

Output

 

For each test case, print the output on one line.

 

Sample Input

3
I am happy today
To be or not to be
I want to win the practice contest

Sample Output

I ma yppah yadot
oT eb ro ton ot eb
I tnaw ot niw eht ecitcarp tsetnoc



题目意思：将每个单词的字符进行反转。


最初代码：

#include<stdio.h>
#include<string.h>
int main()
{
    int n,m,i,j,k;
    char s[1000],x[1000];
    scanf("%d",&n);
    getchar();
    while(n--)
    {
        gets(s);
        m=strlen(s);
        k=0;
        for(i=0; i<=m; i++)
        {
            if(s[i]!=‘ ‘&&s[i]!=0)
            {
                x[k]=s[i];
                k++;
            }
            else
            {
                for(j=k-1; j>=0; j--)
                    printf("%c",x[j]);///逆向输出
                if(s[i]!=0)
                    printf(" ");
                k=0;
            }
        }

        printf("\n");
    }

    return 0;
}

这个代码是一个数组向另外一个数组中倒数，时间复杂度上还是存在着问题，修改之后的新代码如下：

 1 #include<stdio.h>///时间复杂度更小的另外一种方法
 2 #include<string.h>
 3 int main()
 4 {
 5     int t,m,i,j;
 6     char s[10000];
 7     scanf("%d",&t);
 8     getchar();
 9     while(t--)
10     {
11         gets(s);
12         m=strlen(s);
13         for(i=0; i<m; i++)
14         {
15             if(s[i]==‘ ‘)
16             {
17                 for(j=i-1; j>=0&&s[j]!=‘ ‘; j--)
18                 {
19                     printf("%c",s[j]);
20                 }
21                 printf(" ");
22             }
23         }
24         for(i=m-1; i>=0&&s[i]!=‘ ‘; i--)
25         {
26             printf("%c",s[i]);
27         }
28         printf("\n");
29     }
30     return 0;
31 }