计算e的近似值，直到最后一项小于10^-6

Posted 2020-10-27 sad89683

#include<stdio.h>
#include<stdlib.h>
int main()
{
    double i = 0, x = 0,m=0;
    double sum = 1, k = 1;
    do
    x++;
    while ((1.0 / x) < 0.000001);
    for (i = 1; i <= x; i++)
    {
        k = k* i;
        sum += 1.00 / k;
    }
    printf("e≈%.9f", sum);
    system("pause");
    return 0;
}
为什么结果总是2.00000000