1015

Posted 2020-07-08 Si考者

题目大意:

Problem Description

Give you a number on base ten,you should output it on base two.(0 < n < 1000)

 

 

Input

For each case there is a postive number n on base ten, end of file.

 

 

Output

For each case output a number on base two.

 

 

Sample Input

1 2 3

 

 

Sample Output

1 10 11

十进制转二进制

解题思路:

按照定义，对二求余

代码:

#include <iostream>
using namespace std;
int main()
{
    int a,i;
    int b[100];
    while(cin>>a)
    {
        i=0;
        while(a!=0)
        {
            b[i]=a%2;
            a/=2;
            i++;
        }
        for(i--;i>=0;i--)
            cout<<b[i];
        cout<<endl;
    }
    return 0;
}