python 下字符串格式时间比较

Posted 2020-07-08 朝花夕拾

举例：

 1 #-*-coding=utf-8-*-
 2 __author__=‘zhongtang‘
 3 
 4 
 5 import time
 6 strtime1=‘20160518010101‘
 7 strtime2=‘20160518020101‘
 8 
 9 #字符串变成时间数据结构
10 localtime1=time.strptime(strtime1,‘%Y%m%d%H%M%S‘)
11 localtime2=time.strptime(strtime2,‘%Y%m%d%H%M%S‘)
12 
13 print type(localtime1),localtime1
14 print type(localtime2),localtime2
15 
16 
17 #从时间数据结构转换成时间戳
18 time1= time.mktime(localtime1)
19 time2= time.mktime(localtime2)
20 
21 print type(time1),time1
22 print type(time2),time2
23 
24 #时间戳可以直接相减，得到以秒为单位的差额
25 print time2-time1

 

输出结果

1 <type ‘time.struct_time‘> time.struct_time(tm_year=2016, tm_mon=5, tm_mday=18, tm_hour=1, tm_min=1, tm_sec=1, tm_wday=2, tm_yday=139, tm_isdst=-1)
2 <type ‘time.struct_time‘> time.struct_time(tm_year=2016, tm_mon=5, tm_mday=18, tm_hour=2, tm_min=1, tm_sec=1, tm_wday=2, tm_yday=139, tm_isdst=-1)
3 <type ‘float‘> 1463504461.0
4 <type ‘float‘> 1463508061.0
5 3600.0