[Codevs] 线段树练习5

Posted 2020-10-24 xayata

http://codevs.cn/problem/4927/

比较有价值

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <string>


using namespace std;
const int N = 1e5 + 10;

#define oo 1423333339
#define LL long long
#define gg 465432477

#define lson jd << 1
#define rson jd << 1 | 1

struct Node {
    LL l, r, w, f, mx, mi, fg;
    bool qs;
} T[N << 2];
LL n, m, answer, maxn, minn;

inline LL read() {
    LL x = 0, f = 1;
    char c = getchar();
    while(c < ‘0‘ || c > ‘9‘) {if(c == ‘-‘)f = -1; c = getchar();}
    while(c >= ‘0‘ && c <= ‘9‘) x = x * 10 + c - ‘0‘, c = getchar();
    return x * f;
}

void imp(LL jd) {
    T[jd].w = T[lson].w + T[rson].w;
    T[jd].mx = max(T[lson].mx, T[rson].mx);
    T[jd].mi = min(T[lson].mi, T[rson].mi);
}

void down(LL jd) {
    if(T[jd].qs) {
        T[lson].f = 0;
        T[lson].qs = 1;
        T[lson].fg = T[jd].fg;
        T[lson].w = (T[lson].r - T[lson].l + 1) * T[jd].fg;
        T[rson].f = 0;
        T[rson].qs = 1;
        T[rson].fg = T[jd].fg;
        T[rson].w = (T[rson].r - T[rson].l + 1) * T[jd].fg;
        T[lson].mi = T[lson].mx = T[rson].mi= T[rson].mx=T[jd].fg;
        T[jd].fg = 0;
        T[jd].qs = 0;
    }
    if(T[jd].f) {
        T[lson].f += T[jd].f;
        T[lson].w += (T[lson].r - T[lson].l + 1) * T[jd].f;
        T[lson].mi += T[jd].f;
        T[lson].mx += T[jd].f;
        T[rson].f += T[jd].f;
        T[rson].w += (T[rson].r - T[rson].l + 1) * T[jd].f;
        T[rson].mi += T[jd].f;
        T[rson].mx += T[jd].f;
        T[jd].f = 0;
    }
    return ;
}

void build_tree(LL l, LL r, LL jd) {
    T[jd].l = l;
    T[jd].r = r;
    if(l == r) {
        T[jd].w = read();
        T[jd].mx = T[jd].w;
        T[jd].mi = T[jd].w;
        return ;
    }
    LL mid = (l + r) >> 1;
    build_tree(l, mid, lson);
    build_tree(mid + 1, r, rson);
    imp(jd);
}

void Sec_g(LL l, LL r, LL jd, LL x, LL y, LL yj) {
    if(x <= l && r <= y) {
        T[jd].f += yj;
        T[jd].w += (T[jd].r - T[jd].l + 1) * yj;
        T[jd].mi += yj;
        T[jd].mx += yj;
        return ;
    }
    if(T[jd].f || T[jd].qs) down(jd);
    LL mid = (l + r) >> 1;
    if(x <= mid) Sec_g(l, mid, lson, x, y, yj);
    if(y > mid) Sec_g(mid + 1, r, rson, x, y, yj);
    imp(jd);
}

void Sec_set(LL l, LL r, LL jd, LL x, LL y, LL k) {
    if(x <= l && r <= y) {
        T[jd].fg = k;
        T[jd].qs = 1;
        T[jd].w = (T[jd].r - T[jd].l + 1) * T[jd].fg;
        T[jd].mx = k;
        T[jd].mi = k;
        T[jd].f = 0;
        return ;
    }
    LL mid = (l + r ) >> 1;
    if(T[jd].f || T[jd].qs) down(jd);
    if(x <= mid) Sec_set(l, mid, lson, x, y, k);
    if(y > mid) Sec_set(mid + 1, r, rson, x, y, k);
    imp(jd);
}

void Sec_calc(LL l, LL r, LL jd, LL x, LL y) {
    if(x <= l && r <= y) {
        answer += T[jd].w;
        return;
    }
    if(T[jd].f || T[jd].qs) down(jd);
    LL mid = (l + r) >> 1;
    if(x <= mid) Sec_calc(l, mid, lson, x, y);
    if(y > mid) Sec_calc(mid + 1, r, rson, x, y);
}

void Sec_min(LL l, LL r, LL jd, LL x, LL y) {
    if(x <= l && r <= y) {
        minn = min(minn, T[jd].mi);
        return ;
    }
    if(T[jd].f || T[jd].qs)
        down(jd);
    LL mid = (l + r) >> 1;
    if(x <= mid) Sec_min(l, mid, lson, x, y);
    if(y > mid) Sec_min(mid + 1, r, rson, x, y);
}

void Sec_max(LL l, LL r, LL jd, LL x, LL y) {
    if(x <= l && r <= y) {
        maxn = max(maxn, T[jd].mx);
        return ;
    }
    if(T[jd].f || T[jd].qs) down(jd);
    LL mid = (l + r) >> 1;
    if(x <= mid) Sec_max(l, mid, lson, x, y);
    if(y > mid) Sec_max(mid + 1, r, rson, x, y);
}

int main() {
    n = read();
    m = read();
    build_tree(1, n, 1);
    for(LL i = 1; i <= m; i ++) {
        string s;
        cin >> s;
        LL x = read();
        LL y = read();
        if(s == "add") {
            LL k = read();
            Sec_g(1, n, 1, x, y, k);
            continue;
        }
        if(s == "set") {
            LL k = read();
            Sec_set(1, n, 1, x, y, k);
            continue;
        }
        if(s == "sum") {
            answer = 0;
            Sec_calc(1, n, 1, x, y);
            printf("%lld\n", answer);
            continue;
        }
        if(s == "min") {
            minn = oo;
            Sec_min(1, n, 1, x, y);
            printf("%lld\n", minn);
            continue;
        }
        if(s == "max") {
            maxn = -oo;
            Sec_max(1, n, 1, x, y);
            printf("%lld\n", maxn);
            continue;
        }
    }
    return 0;
}