Aiiage Camp Day3 B Bipartite

Posted 2020-10-24 SUSTech TripleH

题意

　　给出T个N，判断哪些是2的整数次幂。

　　T<=10, N<=1e100000.

 

题解

　　N & (N - 1) == 0即为2的整数次幂。

　　学好Java，做遍大数都不怕。

 1 import java.math.BigInteger;
 2 import java.util.Scanner;
 3 
 4 public class Main
 5 {
 6     public static void main(String[] args)
 7     {
 8         Scanner cin = new Scanner(System.in);
 9         int T;
10         T = cin.nextInt();
11         for (int ii = 0; ii < T; ++ii)
12         {
13             BigInteger n = cin.nextBigInteger();
14             if (n.compareTo(BigInteger.ZERO) > 0)
15             {
16                 BigInteger ans = n.and(n.subtract(BigInteger.ONE));
17                 if (ans.compareTo(BigInteger.ZERO) == 0)
18                     System.out.println("Yes");
19                 else
20                     System.out.println("No");
21             }
22             else
23             {
24                 System.out.println("No");
25             }
26         }
27     }
28 }