Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu". Note: zero ("ling") must be handled correctly according to the Chinese tradition. For example, 100800 is "yi Shi Wan ling ba Bai".
Input Specification:
Each input file contains one test case, which gives an integer with no more than 9 digits.
Output Specification:
For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.
Sample Input 1:
-123456789
Sample Output 1:
Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
Sample Input 2:
100800
Sample Output 2:
yi Shi Wan ling ba Bai
#include<iostream>
using namespace std;
string form[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
int tag=0,cnt=0,flag=0;
void read(string s){
for(int i=0;i<s.size();i++){
int pos=s.size()-i;
if(s[i]=='0'){
// 遇到0的时候,记录flag=1,等下次碰到非零的数时候在输出ling,
// 可以避免遇到1001时输出两个ling的情况
flag=1;
}else{
if(flag==1) cout<<" ling"; //
if(tag!=1) cout<<" "; //tag=1时,是开头不能输出空格
if(pos==4)
cout<<form[s[i]-'0']<<" Qian";
else if(pos==3)
cout<<form[s[i]-'0']<<" Bai";
else if(pos==2)
cout<<form[s[i]-'0']<<" Shi";
else
cout<<form[s[i]-'0'];
flag=0; tag=0;
}
}
}
int main(){
string num,s;
cin>>num;
if(num=="0") cout<<"ling"<<endl; // 特例:0
if(num[0]=='-'){
cout<<"Fu "; // 处理负数
num=num.substr(1);
}
for(int i=0;i<num.size();i++){
int pos=num.size()-i;
if(pos==9){ // 九位数的情况
cout<<form[num[i]-'0']<<" Yi";
cnt++;
}
else if(pos<=8&&pos>=5){ // 大于等于5位数的情况
if(i==0) tag=1; //tag=1时,是开头不能输出空格
s=num.substr(i,num.size()-cnt-4);
i+=num.size()-cnt-4-1;
read(s);
cnt+=s.size();
cout<<" Wan";
}else if(pos<=4&&pos>=1){ // 小于等于4位数的情况
if(i==0) tag=1; //tag=1时,是开头不能输出空格
s=num.substr(i,num.size()-cnt);
read(s);
break;
}
}
return 0;
}