beego 导入一个普通的包都会执行init方法，如果是struct就不会执行

Posted 2020-10-22 672530440

default.go

package controllers

import (
    "beego-test/models"
    "beego-test/service"
    "github.com/astaxie/beego"
)

type MainController struct {
    beego.Controller
}

func (c *MainController) Get() {
    c.Data["Website"] = "beego.me"
    c.Data["Email"] = "[e-mail]"
    service.Print()
    models.Mmodel()
    new(service.Service2).Print2()
    c.TplName = "index.tpl"
}

models.go

package models

import (
    "fmt"
)

func init() {
    fmt.Println("...initMmodel...")
}

func Mmodel() {
    fmt.Println("...PrintMmodel...")
}

service.go

package service

import (
    "fmt"
)

func init() {
    fmt.Println("...init...")
}

func Print() {
    fmt.Println("...Print...")
}

service1.go

package service

import (
    "fmt"
)

func init() {
    fmt.Println("...init1...")
}

func Print1() {
    fmt.Println("...Print1...")
}

service2.go

package service

import (
    "fmt"
)

type Service2 struct {
}

func (this *Service2) init() {
    fmt.Println("...init.service2..")
}

func (this *Service2) Print2() {
    fmt.Println("...Print.service2..")
}