动态规划_百炼4122 切割回文

Posted 2020-10-22 mapreduce

 1 #define _CRT_SECURE_NO_WARNINGS  
 2 #include <stdio.h>
 3 #include <math.h>
 4 #include <algorithm>
 5 #include <stdlib.h>
 6 #include <vector>
 7 #include <map>
 8 #include <queue>
 9 #include <string>
10 #include <iostream>
11 #include <ctype.h>
12 #include <string.h>
13 #include <set>
14 #include <stack>
15 #include<functional>
16 using namespace std;
17 #define size 1001
18 #define maxn  1<<30
19 int dp[size];
20 char a[size];
21 /*dp[i]表示的是将前面i个字符切割回文字串时候需要切多少刀
22 然后将字符串从j处切开,字符串变成了
23 1..j  j+1..i
24 能切割的条件是j+1 到i是回文的
25 */
26 bool isSymmetry(int s, int e){
27     while (a[s] == a[e]&&s<=e){
28         s++, e--;
29     }
30     if (s <= e)  return false;
31     return true;
32 }
33 
34 int main(){
35     int T;
36     cin >> T;
37     while (T--){
38         scanf("%s", a + 1);
39         int len = strlen(a+1);
40         for (int i = 1; i <= len; i++){
41             dp[i] = isSymmetry(1, i) ? 0 : i - 1;
42             for (int j = 1; j < i; j++)
43             {
44                 if (isSymmetry(j + 1, i)) dp[i] = min(dp[j] + 1, dp[i]);
45             }
46         }
47         cout << dp[len] << endl;
48     }
49     system("pause");
50     return 0;
51 }