#include <bits/stdc++.h>
using namespace std;
const int inf=1e9;
const int MN=10001;
const int MM=1001;
const int MK=10001;
struct tube
{int p,l/*downward*/,h/*upward*/;}s[MK];
bool cmp(tube a,tube b){return a.p<b.p;}
int n,m,k,cnt=1;
int up[MN],down[MN];
int f[MN][MM];
int dp()
{
for (int i=1;i<=n;++i)
{
for (int j=1;j<=m;++j) f[i][j]=inf;
for (int j=1;j<=m;++j)
if (j-up[i]>0)
f[i][j]=min(f[i][j],min(f[i-1][j-up[i]],f[i][j-up[i]])+1);
for (int j=m-up[i]+1;j<=m;++j) //'=' must be concentrated,for f[i-1][m] must be calced.don't for f[i][m] is twice and cut the '='.
f[i][m]=min(f[i][m],min(f[i][j],f[i-1][j])+1); //!!!
for (int j=1;j<=(m-down[i]);++j)
f[i][j]=min(f[i][j],f[i-1][j+down[i]]);
if (i==s[cnt].p)
{
for (int j=1;j<=m;++j)
if (j>=s[cnt].h || j<=s[cnt].l) f[i][j]=inf;
bool flag=true;
for (int j=1;j<=m;++j)
if (f[i][j]!=inf)
{
flag=false;
break;
}
if (flag) {cout<<"0\n"<<cnt-1; return 0;}
cnt++;
}
}
int ans=inf;
for (int i=1;i<=m;++i) ans=min(ans,f[n][i]);
cout<<"1\n"<<ans;
return 0;
}
int init()
{
cin>>n>>m>>k;
for (int i=1;i<=n;++i)
cin>>up[i]>>down[i];
for (int i=1;i<=k;++i)
cin>>s[i].p>>s[i].l>>s[i].h;
sort(s+1,s+k+1,cmp);
return 0;
}
int main()
{
init();
dp();
return 0;
}
P1941题解|NOIP2014飞扬的小鸟
Posted iyanhang
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