646. Maximum Length of Pair Chain 对链最大长度

Posted 2020-10-21 Long Long Journey

 You are given n pairs of numbers. In every pair, the first number is always smaller than the second number.

Now, we define a pair (c, d) can follow another pair (a, b) if and only if b < c. Chain of pairs can be formed in this fashion.

Given a set of pairs, find the length longest chain which can be formed. You needn‘t use up all the given pairs. You can select pairs in any order.

Example 1:

Input: [[1,2], [2,3], [3,4]]
Output: 2
Explanation: The longest chain is [1,2] -> [3,4]

Note:

1. The number of given pairs will be in the range [1, 1000].

class Solution:
    def findLongestChain(self, pairs):
        """
        :type pairs: List[List[int]]
        :rtype: int
        """
        res = 0
        sortedPairs = sorted(pairs, key=lambda x: (x[0], x[1]))
        pre = -2147483648
        for pair in sortedPairs:
            if pre < pair[0]:
                res += 1
                pre = pair[1]
            elif pair[1] < pre:
                pre = pair[1]
        return res
#pairs = [[1, 2], [2, 3], [5, 2], [3, 4], [3, 10]]
pairs = [[-6, 9], [1, 6], [8, 10], [-1, 4], [-6, -2], [-9, 8], [-5, 3], [0, 3]]
s = Solution()
res = s.findLongestChain(pairs)
print(res)

来自为知笔记(Wiz)