java 线程问题，写一个死锁（原理：只有互相都等待对方放弃资源才会产生死锁）

Posted 2020-10-21 Advancing Swift

package com.swift;

public class DeadLock implements Runnable {
    private boolean flag;

    DeadLock(boolean flag) {
        this.flag = flag;
    }

    public void run() {
        while (true) {
            if (flag) {
                synchronized ("suo1") {
                    System.out.println(Thread.currentThread().getName()+"if....locka");
                    synchronized ("suo2") {
                        System.out.println(Thread.currentThread().getName()+"if.....lockb");
                    }
                }
            } else {
                synchronized ("suo2") {
                    System.out.println(Thread.currentThread().getName()+"else.....lockb");
                    synchronized ("suo1") {
                        System.out.println(Thread.currentThread().getName()+"else....locka");
                    }
                }
            }
        }
    }

    public static void main(String[] args) {
        
        /*
         * 写一个死锁
         */
        //只有互相都等待对方放弃资源才会产生死锁
        new Thread(new DeadLock(true),"线程1").start();
        new Thread(new DeadLock(false),"线程2").start();
    }
}

同步代码块的锁也可以用对象，如LockA.locka

locka对象为静态 公共