ListView优化

Posted 2020-10-20 Mr.Struggle

在getView()方法中，每次都将布局重新加载了一遍，当ListView快速滚动的时候，这就会成为性能的瓶颈。

getView()方法中还有一个convertView参数，这个参数用于将之前加载好的布局进行缓存，以便之后可以进行重用。

因此我们可以通过他来进行优化：

 @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        Fruit fruit = getItem(position);
        View view;
        if (convertView == null) {
            view = LayoutInflater.from(getContext()).inflate(resourceId, parent,
                false);
        } else {
            view = convertView;
        }
        ImageView fruitImage = (ImageView) view.findViewById(R.id.fruit_image);
        TextView fruitName = (TextView) view.findViewById(R.id.fruit_name);
        fruitImage.setImageResource(fruit.getImageId());
        fruitName.setText(fruit.getName());
        return view;
    }

不过，目前我们的这份代码还是可以继续优化的，虽然现在已经不会再重复去加载布局，但是每次在getView()方法中还是会调用View的findViewById()方法来获取一次控件的实例。我们可以借助一个ViewHolder来对这部分性能进行优化：

 @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        Fruit fruit = getItem(position);
        View view;
        ViewHolder viewHolder;
        if (convertView == null) {
            view = LayoutInflater.from(getContext()).inflate(resourceId, parent,
            false);
            viewHolder = new ViewHolder();
            viewHolder.fruitImage = (ImageView) view.findViewById
            (R.id.fruit_image);
            viewHolder.fruitName = (TextView) view.findViewById (R.id.fruit_name);
            view.setTag(viewHolder); // 将ViewHolder存储在View中
        } else {
            view = convertView;
            viewHolder = (ViewHolder) view.getTag(); // 重新获取ViewHolder
        }
        viewHolder.fruitImage.setImageResource(fruit.getImageId());
        viewHolder.fruitName.setText(fruit.getName());
        return view;
    }

    class ViewHolder {

        ImageView fruitImage;

        TextView fruitName;

    }