日期相差的天数计算201307311924.txt

Posted 2020-07-05 夏子藤

输入
1978 10 1 1978 10 1
1978 10 1 1978 10 2              
1978 10 2 1978 10 1
2001 1 1 2000 1 1
2000 1 1 2002 1 1

 

输出
0
1
1
366
731

 

 

 

#include "stdio.h"
int main()
{
 int b[2]={365,366};
   int a[2][13]={0,31,28,31,30,31,30,31,31,30,31,30,31,
                 0,31,29,31,30,31,30,31,31,30,31,30,31};
   int year1,month1,day1,year2,month2,day2;
   int s1,s2,i,s,t,j;
   scanf("%d%d%d%d%d%d",&year1,&month1,&day1,&year2,&month2,&day2);
   if(year1==year2)//同年份的情况
   {
    if(month1>month2)
    {t=month1;month1=month2;month2=t;}
    {t=day1;day1=day2;day2=t;}
    if(month1==month2&&day1>day2)
    {t=day1;day1=day2;day2=t;}
    s1=s2=0;
    j=(year1%400==0||(year1%4==0&&year1%100!=0));
     for(i=0;i<month1;i++)
     {
      s1=s1+a[j][i];
     }
     s1=s1+day1;
     for(i=0;i<month2;i++)
     {
      s2=s2+a[j][i];
     }
     s2=s2+day2;
     if(s1>s2)
     {t=s1;s1=s2;s2=t;}
     s=s2-s1;
   //printf("%d\n",s);
   }
    if(year1>year2)//不同年份的情况
   {
   {t=year1;year1=year2;year2=t;}
   {t=month1;month1=month2;month2=t;}
   {t=day1;day1=day2;day2=t;}
   }
     if(year1<year2)
    {
     s=s1=s2=0;
     j=(year1%400==0||(year1%4==0&&year1%100!=0));
     for(i=0;i<month1;i++)
     {s1=s1+a[j][i];}
     s1=s1+day1;
     s1=b[j]-s1;
     j=(year2%400==0||(year2%4==0&&year2%100!=0));
     for(i=0;i<month2;i++)
     {s2=s2+a[j][i];}
     s2=s2+day2;
     year1+=1;
     j=(year1%400==0||(year1%4==0&&year1%100!=0));
     for(;year1<year2;)
     {
         s=s+b[j];
         year1+=1;
      j=(year1%400==0||(year1%4==0&&year1%100!=0));
     }
     s=s+s1+s2;
    }
     printf("%d\n",s);
     return 0;
}