斐波纳契数列

Posted 2020-10-18 GCat

# -*- coding:utf-8 -*-

#0 1 1 2 3 5 8 13 21 34 55...
#简单的斐波那契数列
s = 20
def fb(s):
    f = []
    a = 0
    b = 1
    while len(f) < s:
        f.append(b)
        b, a = a + b, b
    print(f)
fb(s)

#高级的斐波那契数列
s = 10
def recur_febo(n):
    if n <= 1:
        return n
    else:
        return (recur_febo(n-1)) + recur_febo(n-2)

for i in range(s):
    print(recur_febo(i))