557. Reverse Words in a String III
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Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let‘s take LeetCode contest" Output: "s‘teL ekat edoCteeL tsetnoc" Note: In the string, each word is separated by single space and there will not be any extra space in the string.
I just wanted to use the same logic as Reverse Words in a String II. Step 1. Convert the string to char[] array Step 2. Whenever I encounter a space ‘ ‘ , I call the reverse function ( just to keep the code clean ) Step 3. Repeat till the end! Hope this helps! Thanks for voting :)
public String reverseWords(String s) { char[] s1 = s.toCharArray(); int i = 0; for(int j = 0; j < s1.length; j++) { if(s1[j] == ‘ ‘) { reverse(s1, i, j - 1); i = j + 1; } } reverse(s1, i, s1.length - 1); return new String(s1); } public void reverse(char[] s, int l, int r) { while(l < r) { char temp = s[l]; s[l] = s[r]; s[r] = temp; l++; r--; } }
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557. Reverse Words in a String III
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557. Reverse Words in a String III
557. Reverse Words in a String III