大数相加 a+b

Posted 2020-07-03 让自己不再小小的

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<ctype.h>
#include<math.h>
#define N 1010

char s1[N], s2[N];
int a[N], b[N], c[N];

int main()
{
int T, len1, len2, i, k, cnt=1;
scanf("%d", &T);
getchar();

while(T--)
{
scanf("%s %s", s1, s2);
getchar();

len1=strlen(s1);
len2=strlen(s2);
memset(a, 0, sizeof(a));
memset(b, 0, sizeof(b));
memset(c, 0, sizeof(c));
k=0;
for(i=len1-1; i>=0; i--)
a[k++]=s1[i]-‘0‘;
k=0;
for(i=len2-1; i>=0; i--)
b[k++]=s2[i]-‘0‘;
for(i=0; i<len1 && i<len2; i++)
{
if(a[i]+b[i]+c[i]>9)
{
c[i]=(a[i]+b[i]+c[i])%10;
c[i+1]=1;
}
else
{
c[i]=a[i]+b[i]+c[i];
}
}
while(i<len1)
{
if(c[i]+a[i]>9)
{
c[i]=(c[i]+a[i])%10;
c[i+1]=1;
}
else
{
c[i]=c[i]+a[i];
}
i++;
}
while(i<len2)
{
if(c[i]+b[i]>9)
{
c[i]=(c[i]+b[i])%10;
c[i+1]=1;
}
else
{
c[i]=c[i]+b[i];
}
i++;
}

i=N-1;
while(!c[i]) i--;

if(cnt>1)
printf("\n");

printf("Case %d:\n", cnt++);
printf("%s + %s = ", s1, s2);

for(; i>=0; i--)
printf("%d", c[i]);
printf("\n");
}
return 0;
}