HDU-5980

Posted 2020-10-15 Kiven#5197

Find Small A

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 2268    Accepted Submission(s): 1083

Problem Description

As is known to all,the ASCII of character ‘a‘ is 97. Now,find out how many character ‘a‘ in a group of given numbers. Please note that the numbers here are given by 32 bits’ integers in the computer.That means,1digit represents 4 characters(one character is represented by 8 bits’ binary digits).

 

 

Input

The input contains a set of test data.The first number is one positive integer N (1≤N≤100),and then N positive integersai (1≤ ai≤2^32 - 1) follow

 

 

Output

Output one line,including an integer representing the number of ‘a‘ in the group of given numbers.

 

 

Sample Input

3 97 24929 100

 

 

Sample Output

3

 

 

关于二进制的理解应用问题，8位即2^8==256，则每个数%256若==97，则sum++

 

AC代码：

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 
 4 int main(){
 5     ios::sync_with_stdio(false);
 6     int t,x;
 7     cin>>t;
 8     int sum=0;
 9     while(t--){
10         cin>>x;
11         while(x>0){
12             if(x%256==97){
13                 sum++;
14             }
15             x/=256;
16         }
17     }
18     cout<<sum<<endl;
19     return 0;
20 }