结对项目进展

Posted 2020-07-03

目前对代码进行了些改动，将程序进行了一些封装，优化了一点代码。

由于之前的要求有所改动，先前是将题目从txt中读取，现在改成自动生成算式，存入txt中再进行读操作。

void create(){

    srand((unsigned) time(NULL));

    int len;

    int operate;

    int op0,op1,op2;

    int exibrac,brac1,brac2;

    char op;

    do{

        len = rand() % 11;

    }while(len<=2);

         

    exibrac = rand() % 2;//0不存在，1存在括号

    brac1 = rand() % (len-1);

    FILE *fp = fopen("test.txt","w+");

    operate = len-1;

    op1 = rand() % 100;

    op0 = rand() % 2;

 

    if(len-operate==brac1 && exibrac == 1){

        op = ‘(‘;

        fprintf(fp , "%c" , op );

        brac2 = brac1 + 1 + rand() % (len-brac1-1);

    }

    if(op0==0){

        fprintf(fp , "%d" ,op1);

    }

    else

    {

        fprintf(fp , "%d" ,op1);

        op=‘|‘;

        fprintf(fp , "%c" ,op);

        op1 = 2 + rand() % 98;

        fprintf(fp , "%d" ,op1);

    }

    while(operate>0){

        op2=rand() % 4;

        switch(op2){

        case 0:

            op = ‘+‘;

            break;

        case 1:

            op = ‘-‘;

            break;

        case 2:

            op = ‘*‘;

            break;

        case 3:

            op = ‘/‘;

            break;

        }

        operate--;

        fprintf(fp , "%c" , op );

 

        if(len-operate==brac1 && exibrac == 1){

            op = ‘(‘;

            fprintf(fp , "%c" , op );

            brac2 = brac1 + 1 + rand() % (len-brac1-1);

        }

//1+(2+3+4

        op1 = rand() % 100;

        op0 = rand() % 2;

        if(op0==0){

            fprintf(fp , "%d" ,op1);

        }

        else

        {

            fprintf(fp , "%d" ,op1);

            op=‘|‘;

            fprintf(fp , "%c" ,op);

            op1 = 2 + rand() % 98;

            fprintf(fp , "%d" ,op1);

        }

        if(len-operate==brac2){

            op = ‘)‘;

            fprintf(fp , "%c" , op );

        }

    }

    fclose(fp);

}