1.实现一个用户登陆接口

Posted 2020-10-14

1.实现一个用户登陆接口

需求：

1.登陆前判断是否在黑名单中blacklist.txt，如存在提示用户被锁定 
2.读取密码文件passwd.txt登陆，登录失败3次就锁定账号，加入黑名单，提示用户是否继续.

 1 # -*- coding:utf-8 -*-
 2 # Author: JACK ZHAO
 3 # 需求：
 4 # 实现一个用户登陆接口
 5 # 1.登陆前判断是否在黑名单中blacklist.txt，如存在提示用户被锁定
 6 # 2.读取密码文件passwd.txt登陆，登录失败3次就锁定账号，加入黑名单，提示用户是否继续
 7 
 8 import os
 9 import fileinput
10 
11 status_sucess_flag=0
12 user_lock_flag=0
13 
14 if not os.path.exists("blacklist.txt"):
15     file_create = open("blacklist.txt","w") #创建黑名单
16     file_create.close()
17 
18 while True:
19     if status_sucess_flag == 1 or user_lock_flag == 1:
20         break
21     for i in range(3):
22         if status_sucess_flag == 1:
23             break
24         username = input("Usrname:")
25         password = input("Password:")
26         for line in fileinput.input("blacklist.txt"): #逐行读取
27             black_username = line.strip("\n")
28             if username == black_username:
29                 print("The user is locked, please contact the administrator.")
30                 user_lock_flag =1
31                 break
32         if user_lock_flag == 1:
33             break
34         file_object = open(‘passwd.txt‘, ‘r‘)  # 打开读取密码文件
35         while True:
36             line = file_object.readline().strip("\n")
37             _username = line.split(":")[0]
38             _password = line.split(":")[-1] #空格切割字符,取最后一个元素
39             if username == _username and password == _password:
40                 print("Welcome {_name} login..".format(_name=username))
41                 status_sucess_flag = 1
42                 break
43             if not line:
44                 print("Login failed.Please check Username or Password.")
45                 break
46     else:
47         print("Try more than 3 times,Has been locked.")
48         file_blacklist = open(‘blacklist.txt‘,‘a‘) #追加方式打开黑名单
49         file_blacklist.write(username)
50         file_blacklist.write("\n")
51         file_blacklist.close()
52         continuet_to_confirm = input("Continuet to confirm [y/n]:")
53         if continuet_to_confirm == "n":
54             print("You‘ve quit.")
55             break