Python编写某个时刻完成某个任务

Posted 2020-10-13 onlyhold

<?xml version="1.0"?>
<data>
    <work name="work1">
        <message>上课</message>
        <showtime>2017-11-04 11:38:20</showtime>
    </work>
    <work name="work2">
        <message>参加XXX会议</message>
        <showtime>2017-11-04 11:38:22</showtime>
    </work>
    <work name="work3">
        <message>参加XXX聚会</message>
        <showtime>2017-11-04 11:38:25</showtime>
    </work>
</data>

# _*_ encoding:utf-8 _*_
__data__ = ‘ 8:58‘

import os,sys
from datetime import datetime
import xml.etree.cElementTree as ET


class ClockMsg():

    def ShowMsg(self, message):
        print (message)

    def WaitTime(self, message, showtime):
        strnext_time = datetime.strptime(showtime, "%Y-%m-%d %H:%M:%S") #提醒时间
        while True:
            str_now = datetime.now()  #获取当前时间
            str_now_time = str_now.strftime(‘%Y-%m-%d %H:%M:%S‘)

　　　　　　　if str(str_now_time) > str(strnext_time):

　　　　　　　　　　self.ShowMsg("输入时间不能早于当前时间")

    　　　　　　　　return

            if str(str_now_time) == str(strnext_time):
                self.ShowMsg(message)
                return

    def GetMsg(self):
        tree = ET.parse("message.xml") #打开xml文档
        root = tree.getroot()   #获得root节点
        for work in root.findall(‘work‘):   #找到root节点下的所有work节点
            message = work.find(‘message‘).text    #子节点下节点message的值
            showtime = work.find(‘showtime‘).text   #子节点下节点showtime的值
            self.WaitTime(message, showtime)

if __name__ == "__main__":
    clockmsg = ClockMsg()
    clockmsg.GetMsg()