二次方程优化之 Quadratic Form
Posted Mr.ZeroW
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=================2017-11-08==============
MATLAB版本低,没有求hessian矩阵的函数,写了一个,需要的拿走
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % -------------------------- %INPUT %f: funtion; %X: variables vactor; %-------------------------- %OUTPUT %H: Hessian matrix %-------------------------- %Example %syms x y z %f = x^2 + y^2 + z^2; %X = [x, y, z]; %H = hessian(f, X) %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% funtion H = hessian(f, X) H = zeros(length(X)); for i = 1: length(X) df1 = diff(f, X(i)); for j = 1: length(X) df2 = diff(df1, X(j)); H(i, j) = df2; end end
======================给一个求偏导,也就是第一步解偏导方程等于0的函数===================
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % -------------------------- %INPUT %f: funtion; %X: variables vactor; %-------------------------- %OUTPUT %op: optimal point %-------------------------- %Example %f = 2*x1^2 - 24 * x1 + 2 * x2^2 - 8*x2 + 2 * x3^2- 12*x3 + 200; %X = [x1, x2, x3]; %op = first_condition(f, X) %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% function op = first_condition(f, X) constraint = []; for i = 1: length(X) df = diff(f, X(i)); constraint = [constraint, df]; end op1 = solve(constraint); op = []; for i = 1: length(X) s = [\'op1.\' char(X(i))]; a = eval(s); op = [op, a]; end disp(constraint.\')
===========================下面给出用法和输出================
比如说求极值,第一步是偏导等于零的点
给出代码如下:
syms x1 x2 x3 f = 2*x1^2 - 24 * x1 + 2 * x2^2 - 8*x2 + 2 * x3^2- 12*x3 + 200; X = [x1, x2, x3]; op = first_condition(f, X)
输出结果:
就是说在点(6, 2, 3)处取极值
============================更==========================
我们这一次对二次型进行更深的讨论
讨论多变量的正定型、负定型和半正定、半负定
先给出结论:
判断有两种方法:
1.强推特征值法:如果所有的特征值是正,则是正定型;全是负的就是负定型;全是非负,就是半正定型;全是非正,就是半负定型;
2.子式判断法:分两步:
第一步:所有阶的主子式大于0,就是正定型;奇数阶的主子式小于0并且偶数阶的主子式大于0,就是负定型;所有阶的主子式大于等于0或者奇数阶的主子式小于等于0并且偶数阶的主子式大于等于0,转入第二步;除此之外的都是不定型;
第二步:所有阶的子式大于等于0,就是半正定型;奇数阶的子式小于等于0并且偶数阶的子式大于等于0,就是半负定型
在继续下面的讨论时,我想先插入一小段关于相关矩阵的一些说明
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python 练习题:定义一个函数quadratic(a, b, c),接收3个参数,返回一元二次方程ax^2+bx+c=0的两个解