10.27 simulated match

Posted 2020-10-12 yodel

#include<iostream>
#include<cstdio>
#define MN 100000
using namespace std;
#define O(a) freopen(a".in","r",stdin);freopen(a".out","w",stdout); 
#define ct   register int
#define f(c)   for(ct i=1;i<=c;i++)
#define ll  long long
int read(){ct f=1,x=0;char c=getchar();
   for(;c<\'0\'||c>\'9\';c=getchar())if(c==\'-\')f=-1;
   for(;\'0\'<=c&&c<=\'9\';c=getchar())x=(x<<1)+(x<<3)+(c^48);return x*f;}
int n,m,L[MN+5],a[MN+5],A[MN+5];ll sum[MN+5];
int main(){O("implement");n=read();//read the total_num of the operations 
    f(n)if(read()==1){int x=read();//read the number
         sum[i]=sum[i-1]+1;//use sum to mark after each operation\'s total_num of numbers
         L[i]=-1;//L use to mark change_numbers\' num,because here we didn\'t change the numbers before ,so we just set it to -1
         A[i]=x;//use A[i] to mark the new number
         if(m<MN)a[++m]=x;//if it is able to push it into the array just push it(resort the violence)
    }
    //operation 1:pish a number into the tail
        else{int l=read(),c=read();//read the change_numbers\' num and push_times 
            sum[i]=sum[i-1]+1LL*l*c;//use sum to mark after each operation\'s total_num of numbers
            L[i]=l;//mark the change_numbers\' num
            for(int i=1;m<MN&&i<=c;++i)
            //inside the section of 1 to MN,we can make operation in violence(just push them into the tail in violence)
            //this loop means push_times
                for(int j=1;j<=l&&m<MN;++j)
            //inside the section of 1 to MN,we can make operation in violence(just push them into the tail in violence)
            //this loop means change_numbers
                a[++m]=a[j];//push numbers into the tail
            }
    //operation 2:delete the first_several numbers and push them into the tail several times
    for(int Q=read();Q;--Q){//read the total_num of inquiries and make a loop in order to read each inquiry
        ll x;scanf("%lld",&x);//read each enquiry
        int pos=lower_bound(sum+1,sum+n+1,x)-sum;
        //use binary research to find x\'s location 
        L[pos]==-1?printf("%d\\n",A[pos]):printf("%d\\n",a[(x-sum[pos-1]-1)%L[pos]+1]);
        //if it\'s location has not changed,just out num of it\'s location.
        //or ,just out the changed location  
}return 0;}

 

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#include<cstring>
#include<cstdio>
#define MN 1000000
using namespace std;
#define O(a) freopen(a".in","r",stdin);freopen(a".out","w",stdout); 
#define ct   register int
#define f(c)   for(ct i=1;i<=c;i++)
int min(int a,int b){return a<b?a:b;}
typedef  long long ll;
int read(){ct f=1,x=0;char c=getchar();
   for(;c<\'0\'||c>\'9\';c=getchar())if(c==\'-\')f=-1;
   for(;\'0\'<=c&&c<=\'9\';c=getchar())x=(x<<1)+(x<<3)+(c^48);return x*f;}
char st[MN+5];int n,m;
struct data{int ans,l,r;
    friend data operator +(const data&a,const data&b){
        int mn=min(a.l,b.r);return (data){a.ans+b.ans+mn,a.l+b.l-mn,a.r+b.r-mn}; }  };
struct Tree{int l,r;data x;}T[MN*4+5];
void Build(int x,int l,int r){
    if((T[x].l=l)==(T[x].r=r)) {T[x].x=(data){0,st[l]==\'(\',st[l]==\')\'};return;}    
    int mid=l+r>>1;Build(x<<1,l,mid);Build(x<<1|1,mid+1,r);
    T[x].x=T[x<<1].x+T[x<<1|1].x; }
data Query(int x,int l,int r){
    if(T[x].l==l&&T[x].r==r)return T[x].x;int mid=T[x].l+T[x].r>>1;
    if(r<=mid)return Query(x<<1,l,r);
    else if(l>mid)return Query(x<<1|1,l,r);
    else return Query(x<<1,l,mid)+Query(x<<1|1,mid+1,r);}
int main(){O("data");n=read();m=read();
    scanf("%s",st+1);n=strlen(st+1);Build(1,1,n);
    f(m){int l=read(),r=read();printf("%d\\n",2*Query(1,l,r).ans);    }return 0;}

 

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#include<iostream>
#include<cstdio>
#define MN 200000
using namespace std;
#define O(a) freopen(a".in","r",stdin);freopen(a".out","w",stdout); 
#define ct   register int
#define f(c)   for(ct i=1;i<=c;i++)
typedef  long long ll;
int read(){ct f=1,x=0;char c=getchar();
   for(;c<\'0\'||c>\'9\';c=getchar())if(c==\'-\')f=-1;
   for(;\'0\'<=c&&c<=\'9\';c=getchar())x=(x<<1)+(x<<3)+(c^48);return x*f;}
int n,m,head[MN+5],cnt=0,a[MN+5],b[MN+5],c[MN+5],ans=0,vis[MN+5],flag[MN+5];
pair<int,int> q[MN+5];
struct edge{int to,next,w;}e[MN*2+5];
inline void ins(int f,int t,int w){e[++cnt]=(edge){t,head[f],w};head[f]=cnt;e[++cnt]=(edge){f,head[t],w};head[t]=cnt; }
void dfs(int x,int fa,int fat){ vis[x]=1;int top=0;
    for(int i=head[x];i;i=e[i].next)
        if(!vis[e[i].to]) dfs(e[i].to,e[i].w,x);
    for(int i=head[x];i;i=e[i].next)
        if(e[i].to!=fat&&!flag[e[i].w])
             q[++top]=make_pair(e[i].to,e[i].w);
    if(fa)q[++top]=make_pair(fat,fa);
    for(int i=2;i<=top;i+=2)a[++ans]=q[i].first,b[ans]=x,c[ans]=q[i-1].first,flag[q[i].second]=flag[q[i-1].second]=1;}
int main(){O("graph");n=read();m=read();
    f(m)ins(read(),read(),i);f(n)if(!vis[i]) dfs(i,0,0);
    printf("%d\\n",ans);f(ans)printf("%d %d %d\\n",a[i],b[i],c[i]); return 0;}