连接查询和分组查询

Posted 2020-10-12 雅俗共赏

1.在SQL Server语言中叫做分组查询，分组查询采用Group  BY 子句实现。

二，多列分组查询

2.分组查询还可以按照多个列来进行分组。

 

使用Group   BY 关键字时，是有限制的，在SELECT 列表中可以指定列是有限制的，仅允许以下几项。

 

被分组的列为每个分组返回一个值，

 

--查询年级所拥有的人数 select GradeId as 年级,COUNT(Phone) as 人数 from Student

group by GradeId 

--根据性别进行分组 select Sex as 性别,COUNT(*) as 人数

from Student group by Sex

--查询每门课程的平均分 select SubjectId as 课程编号,AVG(StudentResult) as 平均分

from Result group by SubjectId

 

--按地区分类，查询地区的人数 select COUNT(*) as 人数,Address as 地址

from Student group by Address

 

--查询每门课程的平均分，并且按照分数由低到高的顺序排列显示 select SubjectId as 课程编号,AVG(StudentResult) as 平均分

from Result group by SubjectId order by AVG(StudentResult) desc

 

--统计每学期男女同学的人数 select COUNT(*) as 人数,GradeId as 年级,Sex as 性别

from Student Group by GradeId,Sex order by GradeId --性别：男和女 年级：1，2，3

 

--如何获得总人数超过2人的年级 select COUNT(*) as 人数,GradeId as 年级,Sex as 性别

from Student Group by GradeId,Sex having COUNT(*)>=2 order by GradeId

 

--出生日期大于1990年的学生,获得总人数超过2人的年级 select COUNT(*) as 人数,GradeId as 年级,Sex as 性别

from Student where BornDate >‘1990/01/01‘ Group by GradeId,Sex having COUNT(*)>=2 order by GradeId

 

 

--同时从这两个表中取得数据 select Student.StudentName as 姓名,Result.StudentResult as 成绩, Result.SubjectId AS 科目编号

from Student,Result where Student.StudentNo=Result.StudentNo

--内链接 select S.StudentName as 姓名,R.StudentResult as 成绩, R.SubjectId AS 科目编号

from Result as R inner join Student as S on(S.StudentNo=R.StudentNo)

 

select S.StudentName as 姓名,R.StudentResult as 成绩, SU.SubjectName AS 科目名称

from Result as R inner join Student as S on(S.StudentNo=R.StudentNo) inner join Subject as SU on(R.SubjectId=SU.SubjectId)

 

select Student.StudentName as 姓名,Result.StudentResult as 成绩, Subject.SubjectName AS 科目名称

from Student,Result,Subject where Student.StudentNo=Result.StudentNo and Result.SubjectId=Subject.SubjectId

--左外连接

select S.StudentName,R.SubjectId,R.StudentResult

From Student AS S LEFT JOIN Result as R on(S.StudentNo=R.StudentNo)

--右外连接 select S.StudentName,R.SubjectId,R.StudentResult

From Result AS R RIGHT JOIN Student as S on(S.StudentNo=R.StudentNo)