Hamming Distance

Posted 2020-10-11 Just DO IT by luckygxf

很久没刷leetcode了

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Note:
0 ≤ x, y < 231.

Example:

Input: x = 1, y = 4

Output: 2

Explanation:
1   (0 0 0 1)
4   (0 1 0 0)
       ↑   ↑

The above arrows point to positions where the corresponding bits are different.
大意：找出两个整数二进制中不同位数
思路：
1. 两个数异或 z
2. 找出z中1的个数

public static int hammingDistance(int x, int y) {
        int z = x ^ y;
        int count = 0;
        while(z != 0){
            z = (z & (z - 1));
            count ++;
        }
        return count;
    }