jQuery对象数组排序

Posted 2020-10-11 孟夏草木长

如何对下列对象数组排序，要将weekday相同的放在一块，并按时间升序：

[
{"start":"14:01","end":"16:00","weekday":1}
{"start":"10:00","end":"12:00","weekday":0},
{"start":"14:01","end":"16:00","weekday":0},
{"start":"10:00","end":"12:00","weekday":1},
{"start":"12:01","end":"14:00","weekday":1},
{"start":"12:01","end":"14:00","weekday":0},
]

Jquery对排序提供了一个方法：sort()。但是这个只是针对string int这样的原始类型的。对对象，对象数组不行。

对对象，对象数组我们可以使用sort()的自定义方法：

数组.sort(　

　　function sortRule(a,b) {
　　　　if(a.属性 > b.属性) return 1 交换位置

　　　　if(a.属性 < b.属性) return -1 不要交换位置

　　　　if(a.属性 = b.属性) return 0 不要交换位置
　　}

)

代码：对它进行两次排序就OK了，先根据时间排序，在根据weekday进行排序。（但是反过来先根据weekday在根据时间排序就不行）

var d = [
            {"start":"10:00","end":"12:00","weekday":0},
            {"start":"12:01","end":"14:00","weekday":0},
            {"start":"12:01","end":"14:00","weekday":1},
            {"start":"10:00","end":"12:00","weekday":1},
            {"start":"14:01","end":"16:00","weekday":1},
            {"start":"14:01","end":"16:00","weekday":0}
         ] ;
               
     d.sort(function(a,b){
            if(a.start>b.start) return 1 ;
            if(a.start<b.start) return -1 ;
            return 0 ;
     }) ;
     d.sort(function(a,b){
            if(a.weekday>b.weekday) return 1 ;
            if(a.weekday<b.weekday) return -1 ;
            return 0 ;
     })