598. Range Addition II

Posted bernieloveslife

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了598. Range Addition II相关的知识,希望对你有一定的参考价值。

Given an m * n matrix M initialized with all 0‘s and several update operations.

Operations are represented by a 2D array, and each operation is represented by an array with two positive integers a and b, which means M[i][j] should be added by one for all 0 <= i < a and 0 <= j < b.

You need to count and return the number of maximum integers in the matrix after performing all the operations.

Example 1:

Input: 
m = 3, n = 3
operations = [[2,2],[3,3]]
Output: 4
Explanation: 
Initially, M = 
[[0, 0, 0],
 [0, 0, 0],
 [0, 0, 0]]

After performing [2,2], M = 
[[1, 1, 0],
 [1, 1, 0],
 [0, 0, 0]]

After performing [3,3], M = 
[[2, 2, 1],
 [2, 2, 1],
 [1, 1, 1]]

So the maximum integer in M is 2, and there are four of it in M. So return 4.

Note:

    1. The range of m and n is [1,40000].
    2. The range of a is [1,m], and the range of b is [1,n].
    3. The range of operations size won‘t exceed 10,000

 

class Solution(object):
def maxCount(self, m, n, ops):
"""
:type m: int
:type n: int
:type ops: List[List[int]]
:rtype: int
"""
p = m
q = n
for i in ops:
if p>i[0]:
p = i[0]
if q>i[1]:
q = i[1]
return p*q

以上是关于598. Range Addition II的主要内容,如果未能解决你的问题,请参考以下文章

598. Range Addition II

[leetcode-598-Range Addition II]

[LeetCode] 598. Range Addition II

LeetCode - 598. Range Addition II

LeetCode 598. Range Addition II (区域范围内加法)

[LeetCode&Python] Problem 598. Range Addition II