537. Complex Number Multiplication
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Given two strings representing two complex numbers.
You need to return a string representing their multiplication. Note i2 = -1 according to the definition.
Example 1:
Input: "1+1i", "1+1i" Output: "0+2i" Explanation: (1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i, and you need convert it to the form of 0+2i.
Example 2:
Input: "1+-1i", "1+-1i" Output: "0+-2i" Explanation: (1 - i) * (1 - i) = 1 + i2 - 2 * i = -2i, and you need convert it to the form of 0+-2i.
Note:
- The input strings will not have extra blank.
- The input strings will be given in the form of a+bi, where the integer a and b will both belong to the range of [-100, 100]. And the output should be also in this form.
题目含义:求两个复数的乘法
思路:根据复数乘法公式 (a+bi)(c+di) = (ac-bd)+(ad+bc)i
1 public String complexNumberMultiply(String a, String b) { 2 String[] A = a.split("\\+"); 3 String[] B = b.split("\\+"); 4 int a1 = Integer.parseInt(A[0]); 5 int b1 = Integer.parseInt(A[1].replace("i","")); 6 7 int a2 = Integer.parseInt(B[0]); 8 int b2 = Integer.parseInt(B[1].replace("i","")); 9 return (a1*a2 - b1*b2)+"+"+(a1*b2 + a2*b1) +"i"; 10 11 }
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