函数组合

Posted 2020-10-10 风吹麦浪打

const add1 = (x) => x + 1
const mul3 = (x) => x * 3
const div2 = (x) => x / 2
//每个函数都要return 进行传参数的
div2(mul3(add1(add1(0)))) // => 3

const compose = (...fns) => {
  return x => fns.reduceRight((v, f) => f(v), x);
}
//调用

compose (add1,mul3,div2)