PAT1041: Be Unique
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1041. Be Unique (20)
Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 104]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.
Input Specification:
Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=105) and then followed by N bets. The numbers are separated by a space.
Output Specification:
For each test case, print the winning number in a line. If there is no winner, print "None" instead.
Sample Input 1:7 5 31 5 88 67 88 17Sample Output 1:
31Sample Input 2:
5 888 666 666 888 888Sample Output 2:
None
思路
和1084差不多的思路,队列q记录顺序,字典dic记录是否重复出现。遍历q的时候查下字典,输出第一个满足"仅出现一次"的数字即可。
代码
#include<iostream> #include<map> #include<iterator> #include<queue> using namespace std; int main() { int N; while(cin >> N) { map<int,int> dic; queue<int> q; for(int i = 0;i < N;i++) { int value; cin >> value; if(dic.count(value) > 0) dic[value] = -1; else { q.push(value); dic.insert(pair<int,int>(value,1)); } } bool check = false; while(!q.empty()) { if(dic[q.front()] > 0) { check = true; cout << q.front(); break; } q.pop(); } if(!check) cout << "None" << endl; } }
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PAT甲级1041 Be Unique (20 分)(多重集)