9.24 simulated match

Posted 2020-10-09 yodel

 

 

#include <bits/stdc++.h>
#define INF 0x3f3f3f3f
#define init(a) freopen(a".in","r",stdin);freopen(a".out","w",stdout); 
#define mm(a,b)  memset(a,b,sizeof(a))
#define fr(i,a,b)  for(int i=a;i<=b;i++)
using namespace std;
int read(){int x=0,f=1;char c=getchar();
    for(;c<\'0\'||c>\'9\';c=getchar())if(c==\'-\')f=-1;
    for(;\'0\'<=c&&c<=\'9\';c=getchar())x=(x<<3)+(x<<1)+(c^48);return x*f;}
struct path{int to,v;};
struct node{int num,v;bool operator <(const node &b) const{return v>b.v;}};
vector<path> g[10001];
priority_queue<node> q;
int m,n,k,ans,dist[10001][21];
bool vis[10001][21];
int min(int a,int b){return a<b?a:b;}
void dij(){node now;mm(dist,INF),mm(vis,0);
    dist[1][0]=0;q.push((node){1,0});
    while(!q.empty()){now=q.top();q.pop();
        int t1=now.num%(n+1),t2=now.num/(n+1);
        vis[t1][t2]=true;
        fr(i,0,int(g[t1].size())-1){path t=g[t1][i];
            if((!vis[t.to][t2])&&dist[t.to][t2]>dist[t1][t2]+t.v){
                dist[t.to][t2]=dist[t1][t2]+t.v;
                q.push((node){t2*(n+1)+t.to,dist[t.to][t2]});}
            if((!vis[t.to][t2+1])&&t2<k&&dist[t.to][t2+1]>dist[t1][t2]){
                dist[t.to][t2+1]=dist[t1][t2];
                q.push((node){(t2+1)*(n+1)+t.to,dist[t.to][t2+1]});}
        }}}
int main(){init("school");n=read(),m=read(),k=read();
    fr(i,1,m){int a=read(),b=read(),v=read();
        g[a].push_back((path){b,v});g[b].push_back((path){a,v});}
    dij();ans=INF;fr(i,0,k)ans=min(ans,dist[n][i]);
    printf("%d",ans);return 0;
}

 

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#include <cstdio>
#include <cstring>
int n,mid,dp[2501][5];
#define init(a) freopen(a".in","r",stdin);freopen(a".out","w",stdout); 
#define fr(i,a,b)  for(int i=a;i<=b;i++)
using namespace std;
int read(){int x=0,f=1;char c=getchar();
    for(;c<\'0\'||c>\'9\';c=getchar())if(c==\'-\')f=-1;
    for(;\'0\'<=c&&c<=\'9\';c=getchar())x=(x<<3)+(x<<1)+(c^48);return x*f;}
int min(int a,int b){return a<b?a:b;}
int main(){init("quad");
    n=read();mid=(n-1)>>1;dp[0][0]=1;
    fr(i,1,n)fr(j,1,4)fr(k,1,min(mid,i))dp[i][j]+=dp[i-k][j-1];
    printf("%d",dp[n][4]);return 0;
}

 

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#include <cstdio>
#include <cstring>
#define INF 0x3f3f3f3f
int n,m,t1,t2;
int a[301],b[301];
int dp[501][301];
#define init(a) freopen(a".in","r",stdin);freopen(a".out","w",stdout); 
#define mm(a,b)  memset(a,b,sizeof(a))
#define fr(i,a,b)  for(int i=a;i<=b;i++)
#define fd(i,a,b)  for(int i=a;i>=b;i--)
using namespace std;
int read(){int x=0,f=1;char c=getchar();
    for(;c<\'0\'||c>\'9\';c=getchar())if(c==\'-\')f=-1;
    for(;\'0\'<=c&&c<=\'9\';c=getchar())x=(x<<3)+(x<<1)+(c^48);return x*f;}
int max(int a,int b){return a>b?a:b;}
int main(){init("solve");
    n=read(),m=read();
    fr(i,1,m)a[i]=read(),b[i]=read();
    mm(dp,INF);dp[2][0]=n;int i=2;
    while(dp[i][m]==INF){
        fd(j,m,0)
            if(dp[i][j]!=INF){int k=j+1;
                t1=dp[i][j],t2=dp[i+1][j]=n;
                while(t1>=a[k]&&t2>=b[k])t1-=a[k],t2-=b[k],
                  dp[i][k]=dp[i][k]==INF?t1:max(dp[i][k],t1),
                  dp[i+1][k]=dp[i+1][k]==INF?t2:max(dp[i+1][k],t2),k++;
            }i++;}printf("%d",i);return 0;}

 

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#include<cstdio>
#define inf 1e9
#define N 100005
#define S1 dis[x]+e[i].v
#define S2 sdis[x]+e[i].v
using namespace std;
//--------------------------
template<class T>inline void cin(T&x){
    static char c;static int y;
    for(c=getchar(),x=0,y=1;c<48||57<c;c=getchar())if(c==\'-\')y=-1;
    for(;48<=c&&c<=57;c=getchar())x=((x+(x<<2))<<1)+(c^\'0\');
    x*=y;}
void outint(int x){if(x>=10) outint(x/10);putchar(x%10+\'0\');}
//--------------------------optimization above
struct node{int to,next,v;}e[N<<1];//e:edge
int head[N],cnt;//cnt:counter,head:point
void insert(int x, int y, int v){e[++cnt].to=y;e[cnt].next=head[x];e[cnt].v=v;head[x]=cnt;}
int n,m,dis[N],sdis[N],q[N<<2];
bool inq[N];
void SPFA(){for(int i=1;i<=n;i++)dis[i]=sdis[i]=inf;
    dis[1]=0; q[0]=1; int l=0,r=1,t; inq[1]=1;//initialization,set the first dis as 0,and push it into the queue,and make it enter_mark true
    while (l<r){int x=q[l++];//if the queue is empty,just set x as the queue_head ,and then renew the queue_head
        for (int i=head[x];i;i=e[i].next){t=e[i].to;//from the first point ,keep going next
        if (dis[t]>S1){sdis[t]=dis[t];dis[t]=S1;if (!inq[t])inq[t]=1,q[r++]=t;}
        //old solution can make better case
        //make second_solution as the old solution,renew the old solution,++++if it has not enter queue,enter it and then mark it true
        if (dis[t]<S1&&sdis[t]>S1){sdis[t]=S1;if (!inq[t])inq[t]=1,q[r++]=t;}
        //second_solution can make better case
        //change it and then just as++++
        if (sdis[t]>S2){sdis[t]=S2;if (!inq[t])inq[t]=1,q[r++]=t;}
        //if can make second_solution_map\'s better case
        //change it and then just as++++
        }inq[x]=0;//make it false
    }
}
int main(){cin(n),cin(m);int x,y,v;
    for (int i=1; i<=m; i++){cin(x),cin(y),cin(v);insert(x,y,v);insert(y,x,v);}//make edge
    SPFA();outint(sdis[n]);return 0;
}//quick and easy,so this is the best solution 
//noted by franzl lang