数据结构——带头节点的约瑟夫问题

Posted 2020-10-09 select

链表使用的是带头节点的双向循环链表：

system.h：

 

Status InitList(DuLinkList &L){
L = (DuLinkList)malloc(sizeof(DuLNode));
DuLinkList q,p;
L->next = L;
L->prior = NULL;
q=L;
int n;
cout<<"输入人数n:";
cin>>n;
for(int i=0; i<n; i++){
p=(DuLinkList)malloc(sizeof(DuLNode));
p->data=i+1;
q->next = p;
p->prior = q;
p->next = L;
L->prior = p;
q=p;

}
return OK;
}
Status OutputList(DuLinkList L){
DuLinkList p=L;
cout<<" ";
while(p->next!=L){
p = p->next;
cout<<p->data<<" ";
}
cout<<endl;
return OK;
}
int GetLeghtList(DuLinkList L){
DuLinkList q=L;
int i=0;
while(q->next!=L){
i++;
q = q->next;
}
return i;
}
Status DeleteList(DuLinkList &L,int k,int m){
DuLinkList p=L->next,s;
int j=1,i=1,total,n;
while((p->next)!=L&&j<k){
p = p->next;
j++;
}
if(k!=GetLeghtList(L))
if((p->next)==L || j>k)return ERROR;
total = GetLeghtList(L);
while (total != 1)
{
for (int t = 1; t < m; t++)
{

if(p->next==L)
p=L->next;
else p = p->next;


}
cout<<"第"<<p->data<<"个人出列,";
s = p;
if(p->next==L)
{
p=L->next;
s->prior->next = L;
L->prior = s->prior;
}
else
{
p=s->next;
p->prior = s->prior;
s->prior->next = p;
}
free(s);
n=GetLeghtList(L);
cout<<"还有"<<n<<"人。"<<endl;
total--;

}
cout<<"最后一人是第"<<p->data<<"个人！";
return OK;
}

 

define.h：

#include <iostream.h>
#include <stdlib.h>
#include <stdio.h>
#include <malloc.h>
#define OK 1
#define ERROR 0
#define INFEASIBLE -1
#define OVERFLOW -2

 

function.h：

typedef int ElemType;
typedef int Status;
typedef struct DuLNode{
ElemType data;
struct DuLNode *prior;
struct DuLNode *next;

}DuLNode,*DuLinkList;

 

 

 

 主函数：

#include "define.h"
#include "function.h"
#include "system.h"
int main(int argc, char *argv[]) {
ElemType k,m;
DuLinkList t;
InitList(t);
OutputList(t);
cout<<"输入k,m:";
cin>>k>>m;
DeleteList(t,k,m);
return 0;
}