django 中间件process_exception 如果程序有异常就执行

Posted 2020-10-08

 

def get(self, request, *args,**kwargs):
    int(sss)
    return  HttpResponse(‘login‘)

注意只要有捕获到异常就直接repon。好处可以直接返回500

class M1(MiddlewareMixin):
    def process_request(self, request):
        print(‘m1.process_request‘)

    def process_view(self, request, callback, callback_args, callback_kwargs):
        """
        如果有返回值，则不在继续执行，直接到最后一个中间件的response
        """
        print(‘m1.process_view‘, callback)
        # return HttpResponse(‘Process View返回值‘)
    def process_response(self,request, response):
        print(‘m1.prcess_response‘)
        return response

    def process_exception(self,request,exception):
        print(‘m1.process_exception‘)

class M2(MiddlewareMixin):
    def process_request(self, request):
        print(‘m2.process_request‘)

    def process_view(self, request, callback, callback_args, callback_kwargs):
        """
        如果有返回值，则不在继续执行，直接到最后一个中间件的response
        """
        print(‘m2.process_view‘, callback)
        # return HttpResponse(‘Process View返回值‘)

    def process_response(self,request, response):
        print(‘m2.prcess_response‘)
        return response


    def process_exception(self,request,exception):
        print(‘m2.process_exception‘)
        return HttpResponse(‘500错误‘)

 

 注意如果此时process_view有return  就直接到了reponse不会捕获错误