Servlet入门

Posted 2020-10-08

1. 在tomcat中新建一个day04 web应用,然后在web应用中新建一个WEB-INF/classes文件目录.
2. 在classes文件中新建一个FirstServlet.java文件,内容如下

    1 package cn.jean;
    2 
    3 import java.io.*;
    4 import javax.servlet.*;
    5 
    6 public class FirstServlet extends GenericServlet {
    7     
    8     public void service(ServletRequest req,ServletResponse res)
    9         throws ServletException,java.io.IOException {
   10             OutputStream out = res.getOutputStream();
   11             out.write("hello servlet!!!".getBytes());
   12     }
   13 }

    

3. 编译servlet文件:在calsses文件下,shift+鼠标右键,打开dos窗口
   编辑命令 set classpath=%classpath%;.........servlet-api.jar
   编译javac : javac -d . FirstServlet.java

4. 在WEB-INF目录中新建web.xml文件,配置servlet的对外访问路径

 

 1 <?xml version="1.0" encoding="ISO-8859-1"?>
 2 <web-app xmlns="http://java.sun.com/xml/ns/javaee"
 3   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 4   xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
 5                       http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
 6   version="3.0">
 7   
 8   <servlet>
 9         <servlet-name>FirstServlet</servlet-name>
10         <servlet-class>cn.jean.FirstServlet</servlet-class>
11   </servlet>
12   
13   <servlet-mapping>
14         <servlet-name>FirstServlet</servlet-name>
15         <url-pattern>/FirstServlet</url-pattern>
16   </servlet-mapping>  
17   
18 </web-app>