组合数据类型练习，英文词频统计实例

Posted 2020-10-07 23许捷凯

1、列表实例：由字符串创建一个作业评分列表，做增删改查询统计遍历操作。例如，查询第一个3分的下标，统计1分的同学有多少个，3分的同学有多少个等

score = list(\'012332211\')
print(\'分数为：\',score)
print(\'1分的同学个数：\',score.count(\'1\'))
print(\'3分的同学个数：\',score.count(\'3\'))
print(\'第一个3分同学的下标为：\',score.index(\'3\'))
score.append(\'0\')
print(\'添加一个0分在表的末尾：\',score)
score.insert(0,\'3\')
print(\'添加一个3分在表的开头：\',score)
score.pop(1)
print(\'删除第二个分数：\',score)

2、字典实例：建立学生学号成绩字典，做增删改查遍历操作

d={\'赵\':95,\'钱\':86,\'孙\':75,\'李\':84,\'周\':96}
print(\'学生成绩字典\',d)
d[\'吴\']=87
print(\'增加一个学生\')
print(d)
d.pop(\'孙\')
print(\'删除学生孙\')
print(d)
d[\'吴\']=97
print(\'修改学生吴的成绩\')
print(d)
print(\'查找学生赵的成绩:\',d.get(\'赵\'))

3、分别做列表，元组，字典，集合的遍历，并总结列表，元组，字典，集合的联系与区别

 ls = list(\'123456789\')
  ln = tuple(\'123456789\')
  s = {\'01\':\'100\',\'02\':\'99\',\'03\':\'98\',\'04\':\'97\',\'05\':\'96\',\'05\':\'96\',\'06\':\'95\',\'07\':\'98\',\'08\':\'90\',\'09\':\'91\'}
  a= set(\'123456789\')
  print(\'列表:\',ls)
  print(\'元组\',ln)
  print(\'字典\',s)
  print(\'集合\',a)
  print(\'\\n列表的遍历：\')
 for i in ls:
     print(i,\' \',end=\'  \')
 print(\'\\n元组的遍历：\')
 for j in ln:
     print(j,\' \',end=\'  \')
 print(\'\\n字典的遍历：\')    
 for k in s:
     print(k,\'\',end=\'  \')
 print(\'\\n集合的遍历：\')    
 for l in a:
     print(l,\'\',end=\'  \')

4、英文词频统计实例

待分析字符串分解提取单词

1. 待分析字符串
2. 分解提取单词
   1. 大小写 txt.lower()
   2. 分隔符\'.,:;?!-_’
3. 计数字典

   1. 排除语法型词汇，代词、冠词、连词

4. 排序list.sort()
5. 输出TOP(10)

news=\'\'\'It\'s normal for fast food brands to poke fun at their competitors,
but Panera Bread\'s latest social media campaign isn\'t cracking jokes.
It\'s a call for executives everywhere to put their kiddie meals where their
mouth is.
On Wednesday, Panera Bread\'s founder and CEO, Ron Shaich, launched
the #KidsMenuChallenge, a social media campaign that challenges other fast food
executives to spend a week eating the food that\'s served on their own children\'s
menus.\'\'\'
print(\'新闻：\',news)

news=news.lower()#小写
print(\'小写：\',news)

for i in \',.\':#将符号替换成空格
     news=news.replace(i,\' \')
print(\'符号换成空格：\',news)

words=news.split(\' \')#用空格分解每一个单词

dic={}#字典
keys=set(words)#出现的所有单词的集合，字典的key
exc={"a","to","is","at","the",\'\'}#没有意义的、不要的单词
for w in exc:#去掉没有意义的单词
     keys.remove(w)
for i in keys:#记录次数
    dic[i]=words.count(i)
wc=list(dic.items())#列表
wc.sort(key=lambda x:x[1],reverse=True)
print(\'记录次数：\')
for i in range(10):#显示10个单词及其次数
     print(wc[i])

5、文本操作

fo=open(\'/Users/Administrator/Desktop/test.txt\',\'r\')
news=fo.read()
fo.close()
exc={\'the\',\'a\',\'to\',\'of\',\'and\',\'on\',\'in\',\'that\'}
news =news.lower()
for i in \'\'\',.?!"\'\'\':
    news=news.replace(i,\' \')

print(news)
words=news.split(\' \')
print(words)
d={}
keys = set(words)
for r in exc:
    keys.remove(r)
for i in keys:
    d[i]=words.count(i)
wc=list(d.items())
wc.sort(key=lambda x:x[1],reverse=True)
for i in range(10):
    print(wc[i])