ACM HDU 1092
Posted
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了ACM HDU 1092相关的知识,希望对你有一定的参考价值。
A+B for Input-Output Practice (IV)
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 108338 Accepted Submission(s): 57340
Problem Description
Your task is to Calculate the sum of some integers.
Input
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.
Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
Sample Input
4 1 2 3 4
5 1 2 3 4 5
0
Sample Output
10 15
解题思路:先输入一个N,然后输入N个整数,N个整数相加的和输出出去。N为0的时候结束输入。
代码如下
#include <stdio.h> int main(void) { int a; int i, sum; int n; while (scanf_s("%d", &n) != EOF) { if (n != 0) { sum = 0; for (i = 0; i < n; i++) { scanf_s("%d", &a); sum += a; } printf("%d\n", sum); } else break; } return 0; }
以上是关于ACM HDU 1092的主要内容,如果未能解决你的问题,请参考以下文章
hdu 1092 A+B for Input-Output Practice (IV)
Hdu 1092 A+B for Input-Output Practice (IV)