java 判断两个时间相差的天数!
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package com.datedaycha;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
import com.sun.org.apache.xerces.internal.impl.xpath.regex.ParseException;
/*
* java 判断两个时间相差的天数
1、实现目标
输入：两个日期
输出：两个日期相差的天数
2、代码实现
方法1：
通过Calendar类的日期比较。注意：这里需要考虑一下：
日期是跨年份的，如一个是2012年，一个是2015年的
年份是分闰年和平年的，各自的天数不同
*/
public class date_day_cha1 {
/**方法1
* date2比date1多的天数
* @param date1
* @param date2
* @return
*/
public static int differentDays_one(Date date1,Date date2)
{
Calendar cal1 = Calendar.getInstance();
cal1.setTime(date1);
Calendar cal2 = Calendar.getInstance();
cal2.setTime(date2);
int day1= cal1.get(Calendar.DAY_OF_YEAR);
int day2 = cal2.get(Calendar.DAY_OF_YEAR);
int year1 = cal1.get(Calendar.YEAR);
int year2 = cal2.get(Calendar.YEAR);
//加个时间日期大小 判断 管他谁大谁小
int diff ;
if(day1<day2) {
diff = day2 - day1;
} else {
diff = day1 - day2;
}
if(year1 != year2) //不同年
{
int timeDistance = 0 ;
for(int i = year1 ; i < year2 ; i ++)
{
if(i%4==0 && i%100!=0 || i%400==0) //闰年
{
timeDistance += 366;
}
else //不是闰年
{
timeDistance += 365;
}
}
//return timeDistance + (day2-day1) ;
return timeDistance + diff ;
}
else //同一年
{
// System.out.println("判断day2 - day1 : " + (day2-day1));
// return day2-day1;
System.out.println("判断day2 - day1 : " + diff);
return diff;
}
}
/* 直接通过计算两个日期的毫秒数，他们的差除以一天的毫秒数，即可得到我们想要的两个日期相差的天数。*/
/**
* 通过时间秒毫秒数判断两个时间的间隔
* @param date1
* @param date2
* @return
*/
public static int differentDaysByMillisecond(Date date1,Date date2)
{
//加个时间日期大小 判断 管他谁大谁小
long time1 = date1.getTime();
long time2 = date2.getTime();
long diff ;
if(time1<time2) {
diff = time2 - time1;
} else {
diff = time1 - time2;
}
//int days = (int) ((date2.getTime() - date1.getTime()) / (1000*3600*24));
int days = (int) (diff /(1000*3600*24));
return days;
}
//测试
public static void main(String[] args) throws Exception {
String dateStr = "2017-1-1 0:0:0";
String dateStr2 = "2017-9-14 10:57:01";
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
// SimpleDateFormat format2 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try
{
Date date2 = format.parse(dateStr2);
Date date = format.parse(dateStr);
System.out.println("两个日期的差距 方法1：" + differentDays_one(date,date2));
System.out.println("两个日期的差距 方法2：" + differentDaysByMillisecond(date,date2));
Date d=new Date();
System.out.println(d.getTime());
System.out.println("距离今天-两个日期的差距 方法1：" + differentDays_one(date,d));
System.out.println("距离今天-两个日期的差距 方法2：" + differentDaysByMillisecond(d,date));
} catch (ParseException e) {
e.printStackTrace();
}
}
}
方法2：package com.datedaycha;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;
import com.sun.org.apache.xerces.internal.impl.xpath.regex.ParseException;
/**
* 时间相距
* @author LC
* @version 1.0
* @date 2017-9-14 10:59:04
*/
public class date_day_cha2 {
/**
* 两个时间之间相差距离多少天
* @param one 时间参数 1：
* @param two 时间参数 2：
* @return 相差天数
*/
public static long getDistanceDays(String str1, String str2) throws Exception{
DateFormat df = new SimpleDateFormat("yyyy-MM-dd");
Date one;
Date two;
long days=0;
try {
one = df.parse(str1);
two = df.parse(str2);
long time1 = one.getTime();
long time2 = two.getTime();
long diff ;
if(time1<time2) {
diff = time2 - time1;
} else {
diff = time1 - time2;
}
days = diff / (1000 * 60 * 60 * 24);
} catch (ParseException e) {
e.printStackTrace();
}
return days;
}
/**
* 两个时间相差距离多少天多少小时多少分多少秒
* @param str1 时间参数 1 格式：1990-01-01 12:00:00
* @param str2 时间参数 2 格式：2009-01-01 12:00:00
* @return long[] 返回值为：{天, 时, 分, 秒}
* @throws Exception
*/
public static long[] getDistanceTimes(String str1, String str2) throws Exception {
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date one;
Date two;
long day = 0;
long hour = 0;
long min = 0;
long sec = 0;
try {
one = df.parse(str1);
two = df.parse(str2);
long time1 = one.getTime();
long time2 = two.getTime();
long diff ;
if(time1<time2) {
diff = time2 - time1;
} else {
diff = time1 - time2;
}
day = diff / (24 * 60 * 60 * 1000);
hour = (diff / (60 * 60 * 1000) - day * 24);
min = ((diff / (60 * 1000)) - day * 24 * 60 - hour * 60);
sec = (diff/1000-day*24*60*60-hour*60*60-min*60);
} catch (ParseException e) {
e.printStackTrace();
}
long[] times = {day, hour, min, sec};
return times;
}
/**
* 两个时间相差距离多少天多少小时多少分多少秒
* @param str1 时间参数 1 格式：1990-01-01 12:00:00
* @param str2 时间参数 2 格式：2009-01-01 12:00:00
* @return String 返回值为：xx天xx小时xx分xx秒
* @throws Exception
*/
public static String getDistanceTime(String str1, String str2) throws Exception {
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date one;
Date two;
long day = 0;
long hour = 0;
long min = 0;
long sec = 0;
try {
one = df.parse(str1);
two = df.parse(str2);
long time1 = one.getTime();
long time2 = two.getTime();
long diff ;
if(time1<time2) {
diff = time2 - time1;
} else {
diff = time1 - time2;
}
day = diff / (24 * 60 * 60 * 1000);
hour = (diff / (60 * 60 * 1000) - day * 24);
min = ((diff / (60 * 1000)) - day * 24 * 60 - hour * 60);
sec = (diff/1000-day*24*60*60-hour*60*60-min*60);
} catch (ParseException e) {
e.printStackTrace();
}
return day + "天" + hour + "小时" + min + "分" + sec + "秒";
}
//测试
public static void main(String[] args) throws Exception {
String dateStr = "2008-1-1 1:21:28";
String dateStr2 = "2017-9-14 10:57:01";
Long days=getDistanceDays(dateStr, dateStr2);
long[] longdays2;
longdays2=getDistanceTimes(dateStr, dateStr2);
String stringday3= getDistanceTime(dateStr, dateStr2);
System.out.println("返回值return：相差多少天："+days);
System.out.println("返回值return：long[] 返回值为：{天, 时, 分, 秒}----:"+longdays2[0]+"天"+longdays2[1]+"小时"+longdays2[2]+"分"+longdays2[3]+"秒");
System.out.println("返回值return：String 返回值为：xx天xx小时xx分xx秒 -----:"+stringday3);
}
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