Codeforces Round #433 (Div. 2, based on Olympiad of Metropolises) C. Planning

Posted 2020-10-05 早知如此绊人心，何如当初莫相识。

题意：给出每个航班花费和顺序，求新顺序使得花费最少

思路：肯定是花费最大的先决定，二分一下

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 const int N=1e5+100;
 4 typedef long long ll;
 5 
 6 struct node{
 7     ll x;
 8     int id;
 9     ll yy;
10 }a[300004];
11 bool cmp(node p,node q){
12     return p.x>q.x;
13 }
14 bool cmp1(node p,node q){
15     return p.id<q.id;
16 }
17 set<int >s;
18 int main(){
19     int n,k;
20     cin>>n>>k;
21     for(int i=1;i<=n;i++){
22        scanf("%lld",&a[i].x);
23        a[i].id=i;
24        s.insert(i+k);
25     }
26     sort(a+1,a+1+n,cmp);
27     ll sum=0;
28     for(int i=1;i<=n;i++){
29         int xx=a[i].id;
30         int k=*s.lower_bound(xx);
31         a[i].yy=k;
32         sum+=(k-xx)*a[i].x;
33         s.erase(k);
34     }
35     cout<<sum<<endl;
36     sort(a+1,a+1+n,cmp1);
37     for(int i=1;i<=n;i++)
38         printf("%lld ",a[i].yy);
39 }