多级菜单的实现

Posted 2020-10-05 Mrchan9

 

 

利用字典实现多级菜单：

 

area = {
    ‘广西‘:{
        ‘梧州‘:{
            ‘岑溪‘:[‘豆腐酿‘,‘新圩米粉‘,‘茄子酿‘,‘白切鸡‘],
            ‘容县‘:[‘1‘,‘2‘,‘3‘],
            ‘苍梧‘:[‘4‘,‘5‘,‘6‘]
            },
        ‘南宁‘:{
            ‘武鸣区‘:[‘大明山‘,‘伊岭岩‘,‘灵水‘,‘明秀园‘],
            ‘宾阳县‘:[‘鱼生‘,‘宾阳酸辣粉‘]
            }
        },
    ‘广东‘:{
        ‘广州市‘:[‘越秀区‘,‘荔湾区‘,‘‘],
        ‘深圳市‘:[‘福田区‘,‘罗湖区‘,‘宝安区‘],
        ‘珠海市‘:[‘香洲区‘,‘斗门区‘,‘金湾区‘]
        },
    ‘湖南‘:{
        ‘长沙市‘:[‘长沙县‘,‘宁乡县‘,‘雨花区‘],
        ‘湘潭市‘:[‘雨湖区‘,‘湘潭县‘,‘韶山市‘],
        ‘娄底市‘:[‘娄星区‘,‘新化县‘,‘双峰县‘]
          }
}

while True:
    for i in area:
        print(i)

    choice = input(‘\n请输入地方名：‘)
    if choice in area:
        while True:
            for i2 in area[choice]:
                print(‘\t‘,i2)
            choice2 = input(‘\n请输入地方名：‘)
            if choice2 in area[choice]:
                while True:
                    for i3 in area[choice][choice2]:
                        print(‘\t\t‘,i3)
                    choice3 = input(‘\n请输入地方名：‘)
                    if choice3 in area[choice][choice2]:
                            for i4 in area[choice][choice2][choice3]:
                                print(‘\t\t\t‘,i4)
                            choice4 = input(‘\n没有啦，按回车返回上一级：‘)
                            if choice4 == ‘b‘:
                                pass
                            elif choice4 == ‘q‘:
                                exit()
                    if choice3 == ‘b‘:
                        break
                    elif choice3 == ‘q‘:
                        exit()
            if choice2 == ‘b‘:
                break
            elif choice2 == ‘q‘:
                exit()
    if choice == ‘q‘:
        exit()