Express之get,pos请求参数的获取

Posted 2020-10-05 申小贺

Get请求

query参数的获取

url假设:http://localhost:3000/users/zqzjs?name=zhaoqize&word=cool&job[st]=web

路由的定义:

router.get(‘/:name‘, function(req, res, next) { })

 

1.获取?name=zhaoqize这样的参数

req.query.name

 

2.获取&job[st]=web这样的参数

req.query.job.st

 

3.获取?name=zhaoqize参数的另外一种写法(4.x版本中该方法已被废弃)

req.param(‘name‘)

 

4.获取所有参数

JSON.stringify(req.query)

具体代码:

//http://localhost:3000/users/zqzjs?name=zhaoqize&word=cool&job[st]=web

//http://localhost:3000/users/zqzjs

router.get(‘/:name‘, function(req, res, next) {

//4.版本中已被废弃，不建议使用

req.param(‘name‘)；

console.log(JSON.stringify(req.query) || ‘‘)；

}

 

Post请求

post的数据获取

Form Data pName:zqz pWord:job

 

1.获取需要的query参数

req.body.pName

 

具体代码:

router.post(‘/postTest‘,function(req, res, next){ var _html = "[Post]" + "<p><strong>req.body:</strong>"+(JSON.stringify(req.body) || ‘‘)+"</p>" + "<p><strong>req.body.name:</strong>"+(req.body.pName || ‘‘)+"</p>" + "<p><strong>req.body.name:</strong>"+(req.body.pWord || ‘‘)+"</p>"; res.send(_html); })

 

结果:

[Post] req.body:{"pName":"zqz","pWord":"job"} req.body.name:zqz req.body.name:job